## anonymous one year ago x2 + 5x = 14

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1. anonymous

7X=14 x= 2

2. Nnesha

it's not 2x+5x $\huge\rm x^2+5x=14$ set it equal to zero move 14 to the right side so subtract 14 both sides $\huge\rm x^2+5x-14=0$now find two number when you multiply them you should get product of AC and when yo add or subtract them you should get the middle term a , b ,c are $\huge\rm Ax^2+Bx+C=0$ a=leading coefficient b=middle term c=constant term