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Howard-Wolowitz

  • one year ago

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  1. Howard-Wolowitz
    • one year ago
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    @triciaal

  2. Howard-Wolowitz
    • one year ago
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    @peachpi

  3. anonymous
    • one year ago
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    iqr = 3rd quartile - 1st quartile = 4.3 - 1.1 = 3.2 outliers are 1.5*IQR away from quartiles 1.5* 3.2 = 4.8 lowest number FOR NO OUTLIER S= 1st quartile - 1.5*IQR = 1.1-4.8 = -3.7 ***minimum data point is 0.3, which is more than 3.7, so there are no outliers on the low end. highest number FOR NO OUTLIERS = 3rd quartile + 1.5*IQR = 4.3+4.8 = 9.1 ***maximum data point is 10.5, which is more than 9.1, so there ARE outliers on the high end

  4. anonymous
    • one year ago
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    |dw:1442247064084:dw|

  5. Howard-Wolowitz
    • one year ago
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    i see but how could you even word that

  6. anonymous
    • one year ago
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    find the iqr, multiply it by 1.5, then add/subtract it from the q1 and q3, then look at where the max an min are in relation

  7. anonymous
    • one year ago
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    What are you calculating?

  8. Howard-Wolowitz
    • one year ago
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    i dont understand... where are they in relation

  9. Howard-Wolowitz
    • one year ago
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    i did it

  10. Howard-Wolowitz
    • one year ago
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    not sure if im correct though

  11. anonymous
    • one year ago
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    |dw:1442252871514:dw|

  12. anonymous
    • one year ago
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    by the same logic the maximum is an outlier because it's more than 1.5*IQR away from Q3

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spraguer (Moderator)
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