## CherokeeGutierrez one year ago WILL GIVE MEDAL! What is the value of 2x^-2 y^-2 for x=3 and y=-2

1. Rushwr

$2x ^{-2}y ^{-2}$ this what u have said right? Just substitute the values and see

2. CherokeeGutierrez

yes. but i need help

3. Rushwr

which part do u need help

4. CherokeeGutierrez

figuring the whole thing out

5. Rushwr

okai, $2x ^{-2}y ^{-2} = 2 * 3^{-2} * -2^{-2}$ right?

6. CherokeeGutierrez

i guess idk thats why i need help

7. Rushwr

in tha step I have substituted the values of x and y which we are given with ! Did u get that part ?

8. CherokeeGutierrez

yes.

9. Rushwr

When u have a negative exponent like $x ^{-n}$ You can also write it as $\frac{ 1 }{ x ^{n} }$ okai ?

10. CherokeeGutierrez

ok

11. CherokeeGutierrez

ok so what now?

12. Rushwr

I got a little wrong there y also has a negative exponent so we can take that down too ! so it will be $\frac{ 2 }{ 3^{2} * -2^{2} }$

13. CherokeeGutierrez

ok lol i was like why did you dlete it. but anyways i got it. whats next

14. Rushwr

now just simplyfy when u multiply 2 negatives it becomes positive right? we knwo -2 ^2 means -2 x -2 right? so that makes it 4!

15. CherokeeGutierrez

so 2/2?

16. Rushwr

we know 3^2 = 9 $\frac{ 2 }{ 9 * 4 }$

17. Rushwr

did u get it ?

18. CherokeeGutierrez

so 2/36

19. CherokeeGutierrez

but there is no answer like that on here

20. CherokeeGutierrez

ohhh 1/18?

21. CherokeeGutierrez

there is that one