WILL GIVE MEDAL! What is the value of 2x^-2 y^-2 for x=3 and y=-2

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WILL GIVE MEDAL! What is the value of 2x^-2 y^-2 for x=3 and y=-2

Mathematics
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\[2x ^{-2}y ^{-2}\] this what u have said right? Just substitute the values and see
yes. but i need help
which part do u need help

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Other answers:

figuring the whole thing out
okai, \[2x ^{-2}y ^{-2} = 2 * 3^{-2} * -2^{-2}\] right?
i guess idk thats why i need help
in tha step I have substituted the values of x and y which we are given with ! Did u get that part ?
yes.
When u have a negative exponent like \[x ^{-n}\] You can also write it as \[\frac{ 1 }{ x ^{n} }\] okai ?
ok
ok so what now?
I got a little wrong there y also has a negative exponent so we can take that down too ! so it will be \[\frac{ 2 }{ 3^{2} * -2^{2} }\]
ok lol i was like why did you dlete it. but anyways i got it. whats next
now just simplyfy when u multiply 2 negatives it becomes positive right? we knwo -2 ^2 means -2 x -2 right? so that makes it 4!
so 2/2?
we know 3^2 = 9 \[\frac{ 2 }{ 9 * 4 }\]
did u get it ?
so 2/36
but there is no answer like that on here
ohhh 1/18?
there is that one

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