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CherokeeGutierrez

  • one year ago

WILL GIVE MEDAL! What is the value of 2x^-2 y^-2 for x=3 and y=-2

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  1. Rushwr
    • one year ago
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    \[2x ^{-2}y ^{-2}\] this what u have said right? Just substitute the values and see

  2. CherokeeGutierrez
    • one year ago
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    yes. but i need help

  3. Rushwr
    • one year ago
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    which part do u need help

  4. CherokeeGutierrez
    • one year ago
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    figuring the whole thing out

  5. Rushwr
    • one year ago
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    okai, \[2x ^{-2}y ^{-2} = 2 * 3^{-2} * -2^{-2}\] right?

  6. CherokeeGutierrez
    • one year ago
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    i guess idk thats why i need help

  7. Rushwr
    • one year ago
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    in tha step I have substituted the values of x and y which we are given with ! Did u get that part ?

  8. CherokeeGutierrez
    • one year ago
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    yes.

  9. Rushwr
    • one year ago
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    When u have a negative exponent like \[x ^{-n}\] You can also write it as \[\frac{ 1 }{ x ^{n} }\] okai ?

  10. CherokeeGutierrez
    • one year ago
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    ok

  11. CherokeeGutierrez
    • one year ago
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    ok so what now?

  12. Rushwr
    • one year ago
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    I got a little wrong there y also has a negative exponent so we can take that down too ! so it will be \[\frac{ 2 }{ 3^{2} * -2^{2} }\]

  13. CherokeeGutierrez
    • one year ago
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    ok lol i was like why did you dlete it. but anyways i got it. whats next

  14. Rushwr
    • one year ago
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    now just simplyfy when u multiply 2 negatives it becomes positive right? we knwo -2 ^2 means -2 x -2 right? so that makes it 4!

  15. CherokeeGutierrez
    • one year ago
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    so 2/2?

  16. Rushwr
    • one year ago
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    we know 3^2 = 9 \[\frac{ 2 }{ 9 * 4 }\]

  17. Rushwr
    • one year ago
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    did u get it ?

  18. CherokeeGutierrez
    • one year ago
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    so 2/36

  19. CherokeeGutierrez
    • one year ago
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    but there is no answer like that on here

  20. CherokeeGutierrez
    • one year ago
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    ohhh 1/18?

  21. CherokeeGutierrez
    • one year ago
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    there is that one

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