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anonymous

  • one year ago

A carnival game has a bowl with 50 packages with 1 item in each: 25 are marbles, 10 are pieces of gum, and the rest contain a new nickel. If each marble is worth 2 cents, and the pieces of gum are each worth a dime, what is the expected value of a random choice from the bowl? The expected value is= a0 cents.

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  1. triciaal
    • one year ago
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    |dw:1442250466486:dw|

  2. anonymous
    • one year ago
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    whats the bottom numbers for ?

  3. triciaal
    • one year ago
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    should be 15 bags with nickels 50 - 25 - 10

  4. anonymous
    • one year ago
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    then i calculate that and ill get my answer ?

  5. anonymous
    • one year ago
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    so the answer is 15

  6. triciaal
    • one year ago
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    no 15 is the number of bags with nickels for the expected value of a random choice 25*0.02 + 10*0.10 + 15 *0.05

  7. anonymous
    • one year ago
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    i got 2.25

  8. triciaal
    • one year ago
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    not sure if should divide by 50 do you have choices ?

  9. triciaal
    • one year ago
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    sorry i don't know

  10. anonymous
    • one year ago
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    see

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  11. anonymous
    • one year ago
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    help plese

  12. triciaal
    • one year ago
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    2.25 = 225 cents

  13. triciaal
    • one year ago
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    @Nnesha can you help?

  14. anonymous
    • one year ago
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    2.25

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