Clongoria2
  • Clongoria2
Inverse function question. Help please! Explain if possible!
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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Clongoria2
  • Clongoria2
Which function below is the inverse of f(x) = 2x + 3/ 5
Clongoria2
  • Clongoria2
A. f^-1(x) = 5x + 3/2 B. f^-1(x) = 5x - 3/2 C. f^-1(x) = 5/2x + 3 D. f^-1(x) = 5/ 3 -2x
anonymous
  • anonymous
Hello! Is it \[f(x)=\frac{ 2x+3 }{ 5 }\] or \[f(x)=2x+ \frac{ 3}{ 5 }\]?

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Clongoria2
  • Clongoria2
Its the first one. Im having trouble understanding what to do after switching the x and y variables
anonymous
  • anonymous
So you already switched x and y like this? \[ x=\frac{ 2y+3 }{ 5 }\]
Clongoria2
  • Clongoria2
Yes I have
anonymous
  • anonymous
All right! So now multiply 5 on both sides.
anonymous
  • anonymous
What would you get?
Clongoria2
  • Clongoria2
\[5x = 2y + 3\]
anonymous
  • anonymous
Make the equation look like the slope-intercept form: \(y=mx+b\).
anonymous
  • anonymous
Do you know how?
Clongoria2
  • Clongoria2
Do you mean \[2y = 5x + 3\]
Clongoria2
  • Clongoria2
?
anonymous
  • anonymous
Yes, but it should be \(2y = 5x - 3\). :) Now divide both sides by 2, and that's it.
Clongoria2
  • Clongoria2
\[5x - 3 / 2 = y\]
anonymous
  • anonymous
\[y= \frac{ 5x-3 }{ 2 } \] or \[y=\frac{ 5x }{ 2 }-\frac{ 3 }{ 2 }\]
Clongoria2
  • Clongoria2
The first one. Sorry.
anonymous
  • anonymous
Oh, you can write it either way I put it, but it is not \(y=5x-\frac{ 3 }{ 2 }\).
Clongoria2
  • Clongoria2
I know i meant to do \[y = \frac{ 5x - 3 }{ 2}\]
Clongoria2
  • Clongoria2
Thank you so much!
anonymous
  • anonymous
You're welcome! :)

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