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Clongoria2

  • one year ago

Inverse function question. Help please! Explain if possible!

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  1. Clongoria2
    • one year ago
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    Which function below is the inverse of f(x) = 2x + 3/ 5

  2. Clongoria2
    • one year ago
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    A. f^-1(x) = 5x + 3/2 B. f^-1(x) = 5x - 3/2 C. f^-1(x) = 5/2x + 3 D. f^-1(x) = 5/ 3 -2x

  3. anonymous
    • one year ago
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    Hello! Is it \[f(x)=\frac{ 2x+3 }{ 5 }\] or \[f(x)=2x+ \frac{ 3}{ 5 }\]?

  4. Clongoria2
    • one year ago
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    Its the first one. Im having trouble understanding what to do after switching the x and y variables

  5. anonymous
    • one year ago
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    So you already switched x and y like this? \[ x=\frac{ 2y+3 }{ 5 }\]

  6. Clongoria2
    • one year ago
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    Yes I have

  7. anonymous
    • one year ago
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    All right! So now multiply 5 on both sides.

  8. anonymous
    • one year ago
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    What would you get?

  9. Clongoria2
    • one year ago
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    \[5x = 2y + 3\]

  10. anonymous
    • one year ago
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    Make the equation look like the slope-intercept form: \(y=mx+b\).

  11. anonymous
    • one year ago
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    Do you know how?

  12. Clongoria2
    • one year ago
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    Do you mean \[2y = 5x + 3\]

  13. Clongoria2
    • one year ago
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    ?

  14. anonymous
    • one year ago
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    Yes, but it should be \(2y = 5x - 3\). :) Now divide both sides by 2, and that's it.

  15. Clongoria2
    • one year ago
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    \[5x - 3 / 2 = y\]

  16. anonymous
    • one year ago
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    \[y= \frac{ 5x-3 }{ 2 } \] or \[y=\frac{ 5x }{ 2 }-\frac{ 3 }{ 2 }\]

  17. Clongoria2
    • one year ago
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    The first one. Sorry.

  18. anonymous
    • one year ago
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    Oh, you can write it either way I put it, but it is not \(y=5x-\frac{ 3 }{ 2 }\).

  19. Clongoria2
    • one year ago
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    I know i meant to do \[y = \frac{ 5x - 3 }{ 2}\]

  20. Clongoria2
    • one year ago
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    Thank you so much!

  21. anonymous
    • one year ago
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    You're welcome! :)

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