anonymous
  • anonymous
This question is based on Heron's Formula : In a triangle ABC, it is given that (s - a) = 5, (s - b) = 3, (s - c) = 1 where s is the semi perimeter and a, b, c are the sides of the triangle. If the area of the triangle is 3sqrt10 sq. units then the perimeter of the triangle is what???
Mathematics
chestercat
  • chestercat
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phi
  • phi
first, write down Heron's formula
anonymous
  • anonymous
\[Area = \sqrt{s(s-a)(s-b)(s-c)}\]
phi
  • phi
now fill in what you know (from the question)

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anonymous
  • anonymous
I substituted vales and found s=6 but it does not work ......
phi
  • phi
s= is (a+b+c)/2 a+b+c is the perimeter you want 2*s for the answer
anonymous
  • anonymous
I have already tried by substituting values and got s=6 but it is not correct
anonymous
  • anonymous
Options for answer are: a) sqrt15 b) 9 c) 27 d) 18
phi
  • phi
in that case you are the victim of a typo, because the perimeter is 12
anonymous
  • anonymous
but if you take s=6 and find values of a, b and c and then find s by a+b+c/2, you get a different value of s
phi
  • phi
even worse, we find a=1, b= 3 and c= 5 and that cannot be a triangle. (c must be less than 4 to be a triangle)
anonymous
  • anonymous
Right!! I was wondering whether I was wrong in my process or was there a mistake in the question itself.........
phi
  • phi
there is something wrong with the question, as it poses an impossible situation I assume there is a typo in the original givens, but it is difficult (for me) to guess what they really meant.
anonymous
  • anonymous
Thanks anyway for your help.....
phi
  • phi
You can ask your teacher about this one (if you have a teacher).
anonymous
  • anonymous
This question is from last year's paper of some other school.......

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