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anonymous

  • one year ago

This question is based on Heron's Formula : In a triangle ABC, it is given that (s - a) = 5, (s - b) = 3, (s - c) = 1 where s is the semi perimeter and a, b, c are the sides of the triangle. If the area of the triangle is 3sqrt10 sq. units then the perimeter of the triangle is what???

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  1. phi
    • one year ago
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    first, write down Heron's formula

  2. anonymous
    • one year ago
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    \[Area = \sqrt{s(s-a)(s-b)(s-c)}\]

  3. phi
    • one year ago
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    now fill in what you know (from the question)

  4. anonymous
    • one year ago
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    I substituted vales and found s=6 but it does not work ......

  5. phi
    • one year ago
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    s= is (a+b+c)/2 a+b+c is the perimeter you want 2*s for the answer

  6. anonymous
    • one year ago
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    I have already tried by substituting values and got s=6 but it is not correct

  7. anonymous
    • one year ago
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    Options for answer are: a) sqrt15 b) 9 c) 27 d) 18

  8. phi
    • one year ago
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    in that case you are the victim of a typo, because the perimeter is 12

  9. anonymous
    • one year ago
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    but if you take s=6 and find values of a, b and c and then find s by a+b+c/2, you get a different value of s

  10. phi
    • one year ago
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    even worse, we find a=1, b= 3 and c= 5 and that cannot be a triangle. (c must be less than 4 to be a triangle)

  11. anonymous
    • one year ago
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    Right!! I was wondering whether I was wrong in my process or was there a mistake in the question itself.........

  12. phi
    • one year ago
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    there is something wrong with the question, as it poses an impossible situation I assume there is a typo in the original givens, but it is difficult (for me) to guess what they really meant.

  13. anonymous
    • one year ago
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    Thanks anyway for your help.....

  14. phi
    • one year ago
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    You can ask your teacher about this one (if you have a teacher).

  15. anonymous
    • one year ago
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    This question is from last year's paper of some other school.......

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