## anonymous one year ago f(x)=x/(x+1) and g(x)=x^2-1 How do I find this function (f+g)(x)

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1. campbell_st

well $(f + g)(x) = f(x) + g(x)$ so you have $(f+g)(x) = \frac{x}{x + 1} + x^2 - 1$

2. anonymous

Yeah I got that far but then how do I solve that problem? @campbell_st

3. campbell_st

ok... so use a common denominator $(f + g)(x) = \frac{x}{x +1} + \frac{(x^2 -1)(x +1)}{x + 1}$ which becomes $(f + g)(x) = \frac{x}{x +1} + \frac{x^3 + x^2 - x - 1}{x + 1}$ so I'll leave you to collect like terms in the numerator to simplify the equation

4. anonymous

(f+g)(x) = x^3+x^2-2x-1/(x+1)

5. campbell_st

well if you have x - x what do you have... you need to just check the numerator