<3pandas18
  • <3pandas18
Algebra
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<3pandas18
  • <3pandas18
Algebra
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
yes?
<3pandas18
  • <3pandas18
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anonymous
  • anonymous

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anonymous
  • anonymous
Subtract 1 on both sides.
<3pandas18
  • <3pandas18
ok so 5l2x-4l=10
anonymous
  • anonymous
Then divide by 5.
<3pandas18
  • <3pandas18
2x-4=2
<3pandas18
  • <3pandas18
x=3?
anonymous
  • anonymous
Now since it is |2x-4|, there are two solutions. |dw:1442261891996:dw|
<3pandas18
  • <3pandas18
ok first solution im guessing is x=3
anonymous
  • anonymous
Yeah
<3pandas18
  • <3pandas18
but how do i do the second
anonymous
  • anonymous
Distribute -1 to 2x-4
<3pandas18
  • <3pandas18
-3?
anonymous
  • anonymous
|dw:1442262026192:dw|
anonymous
  • anonymous
It's not -3.
<3pandas18
  • <3pandas18
ohhhh ok x=1?
anonymous
  • anonymous
Correct! :)
<3pandas18
  • <3pandas18
omg thanks!!!!!!!
anonymous
  • anonymous
You're welcome! You are one of the smartest I've guided in OS. :)

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