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anonymous
 one year ago
hey guys, some help please..
if f(x,y) = (x^3+y^4) then f(xy)f(yx) at the point (1,2) is.. how would i solve this question. Thanks in advance:D
anonymous
 one year ago
hey guys, some help please.. if f(x,y) = (x^3+y^4) then f(xy)f(yx) at the point (1,2) is.. how would i solve this question. Thanks in advance:D

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ayee_ciera
 one year ago
Best ResponseYou've already chosen the best response.0you would substitute 1 in for x and 2 in for y

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2is it \[\huge f_{xy}f_{yx}\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2partial derivatives?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2no that can't be right, both second partials are zero must be something else

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol yes it is. sorry

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2both partials are zero everywhere

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2\[f(x,y) = (x^3+y^4) \]\] \[f_x(x,y)=3x^2\] so \[f_{xy}(x,y)=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol now i'm confused..

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2the partial wrt x, treat y as a constant so it is just \(3x^2\) then if you take the partial wrt y, there is no y in it, so it is just zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooh okay sorry about that. thanks:D

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2maybe i am not understanding the question correctly

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a multiple choice question. i'm not really sure how to approach the question. could it be that the question is incorrect?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2can you post a screen shot or sommat?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay just give me a second

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my pc is a little bit slow this evening, please bear with me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you able to make that out?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2lol you forgot the exponent!!

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2\[f(x,y) = (x^3+y^4)^5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0LOL oh right i did, hehe SO SORRY!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would i approach this question?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2i think it is still has to be zero, but at now we can compute it first \[f_x=5(x^3+y^3)^4\times 3x^2\] via the chain rule

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2oops gotta run, you will get more help i am sure

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0what exactly are you learning? mixed partials should be the same ordinarily

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a new section of work so im really not too familiar with it

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0ah! so you need to go through the process of doing the derivative in that case, go for it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay cool, thanks dude:D
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