A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Linear algebra question.... see attachment please
anonymous
 one year ago
Linear algebra question.... see attachment please

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you see the attachment?

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.1Yes it is possible.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let's call the matrix on the RHS \(M\), so you have \[{\bf{AB}}={\bf{M}}\] If \({\bf{A}}\neq0\), you can find its inverse \({\bf{A}}^{1}\), which is pretty straightforward since it's 2x2. Then \[{\bf{B}}={\bf{A}}^{1}{\bf{M}}\] Then you can find the inverse of \(\bf{B}\), provided it's not singular.

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.1Both \(\bf{AB}\) and \(\bf{A}\) have full rank.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0^^^ that was my attempt but it did not work out

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.1\[ \det(\mathbf{A})=5(3)(3)=59=4\neq5+9=13 \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see that now!!! is my approach correct?

thomas5267
 one year ago
Best ResponseYou've already chosen the best response.1\[ \mathbf{A}^{1}\text{ and }\mathbf{AB}^{1}\text{ exist.}\\ \mathbf{A}^{1}\mathbf{AB}=\mathbf{B}\\ \mathbf{B}^{1}=\left(\mathbf{A}^{1}\mathbf{AB}\right)^{1}=\left(\mathbf{AB}\right)^{1}\mathbf{A}\\ \left(\left(\mathbf{AB}\right)^{1}\mathbf{A}\right)\mathbf{B}=\left(\mathbf{AB}\right)^{1}\left(\mathbf{A}\mathbf{B}\right)=\mathbf{I}\\ \mathbf{B}\left(\left(\mathbf{AB}\right)^{1}\mathbf{A}\right)=\mathbf{A}^{1}\mathbf{AB}\left(\left(\mathbf{AB}\right)^{1}\mathbf{A}\right)=\mathbf{A}^{1}\left(\mathbf{AB}\left(\mathbf{AB}\right)^{1}\right)\mathbf{A}=\mathbf{I}\\ \therefore \mathbf{B}^{1}=\left(\mathbf{AB}\right)^{1}\mathbf{A} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0^^^ I wish I could see it that way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If I could give you another medal for that answer I would lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.