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anonymous

  • one year ago

Yes . . im back with another question :(( http://prntscr.com/8gfbwi

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  1. anonymous
    • one year ago
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    Ok so look at the question. What are the odds someone will get a shot in every free throw?

  2. anonymous
    • one year ago
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    1 shot ? or would it have to add up to 5000?

  3. anonymous
    • one year ago
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    im guessin it going to be between A or B

  4. anonymous
    • one year ago
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    ok. Good its about one shot guessing. But realize that this will be simulated 5000 times. This means \[5*5000=25000\] That means there will be 25,000 shots total.

  5. anonymous
    • one year ago
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    So in about 419 of those simulations you will have a missed free throw ?

  6. anonymous
    • one year ago
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    Wait.

  7. anonymous
    • one year ago
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    or ? .162*5000=810

  8. anonymous
    • one year ago
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    5000-810=4190

  9. anonymous
    • one year ago
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    Seeing this again. It would seem that it would probably be about 4190.

  10. anonymous
    • one year ago
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    correct it was thanks !

  11. anonymous
    • one year ago
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    Wait which one?

  12. anonymous
    • one year ago
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    4190 was correct indeed !

  13. anonymous
    • one year ago
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    .162*5000=810 then 5000-810=4190

  14. anonymous
    • one year ago
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    ok. :P I was thinking something else when I first glanced at it so lel.

  15. anonymous
    • one year ago
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    yea thanks! kudos !

  16. anonymous
    • one year ago
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    Yup np.

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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