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anonymous
 one year ago
directrix =2 and focus is at (4,3) find equation and the vertex
anonymous
 one year ago
directrix =2 and focus is at (4,3) find equation and the vertex

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jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.12? so..hmmm shouldn't it be an ordered pair? 0,2? 2,0?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually i think the directrix is 2

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well then, you found it already then =)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need help finding the eq and vertex

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well, the directrix should have an equation x = 2? y = 2?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442276451048:dw so.. where do you think the vertex would be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i find equation

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well, right.. 1,3 is correct.. the equation is ahemm notice the distance from the vertex to either, the focus or directrix, is 3 units thus p = 3 and it's also a horizontal parabola thus \(\bf \begin{array}{llll} (y{\color{blue}{ k}})^2=4{\color{purple}{ p}}(x{\color{brown}{ h}}) \\ (x{\color{brown}{ h}})^2=4{\color{purple}{ p}}(y{\color{blue}{ k}})\\ \end{array} \qquad \begin{array}{llll} vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\\ {\color{purple}{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}\qquad thus \\ \quad \\ \begin{array}{llll} (y{\color{blue}{ 3}})^2=4{\color{purple}{ (3)}}(x{\color{brown}{ 1}}) \\ \end{array} \qquad \begin{array}{llll} vertex\ ({\color{brown}{ 1}},{\color{blue}{ 3}})\\ {\color{purple}{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}\)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1because is a horizontal parabola, the "y" is the squared variable

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1would... but need to dash in 1 sec :
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