anonymous
  • anonymous
directrix =-2 and focus is at (4,3) find equation and the vertex
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@freckles
jdoe0001
  • jdoe0001
x=-2?
anonymous
  • anonymous
vertex = -2

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jdoe0001
  • jdoe0001
-2? so..hmmm shouldn't it be an ordered pair? 0,-2? -2,0?
anonymous
  • anonymous
actually i think the directrix is -2
jdoe0001
  • jdoe0001
well then, you found it already then =)
anonymous
  • anonymous
i need help finding the eq and vertex
jdoe0001
  • jdoe0001
well, the directrix should have an equation x = -2? y = -2?
anonymous
  • anonymous
x = -2
jdoe0001
  • jdoe0001
|dw:1442276451048:dw| so.. where do you think the vertex would be?
anonymous
  • anonymous
1,3
anonymous
  • anonymous
how do i find equation
jdoe0001
  • jdoe0001
well, right.. 1,3 is correct.. the equation is ahemm notice the distance from the vertex to either, the focus or directrix, is 3 units thus p = 3 and it's also a horizontal parabola thus \(\bf \begin{array}{llll} (y-{\color{blue}{ k}})^2=4{\color{purple}{ p}}(x-{\color{brown}{ h}}) \\ (x-{\color{brown}{ h}})^2=4{\color{purple}{ p}}(y-{\color{blue}{ k}})\\ \end{array} \qquad \begin{array}{llll} vertex\ ({\color{brown}{ h}},{\color{blue}{ k}})\\ {\color{purple}{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}\qquad thus \\ \quad \\ \begin{array}{llll} (y-{\color{blue}{ 3}})^2=4{\color{purple}{ (3)}}(x-{\color{brown}{ 1}}) \\ \end{array} \qquad \begin{array}{llll} vertex\ ({\color{brown}{ 1}},{\color{blue}{ 3}})\\ {\color{purple}{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}\)
jdoe0001
  • jdoe0001
because is a horizontal parabola, the "y" is the squared variable
jdoe0001
  • jdoe0001
would... but need to dash in 1 sec :|
anonymous
  • anonymous
okay

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