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anonymous

  • one year ago

y+8x= 2x squared +1 solve using complete square

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  1. anonymous
    • one year ago
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    @freckles

  2. pooja195
    • one year ago
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    Can you screenshot the question?

  3. anonymous
    • one year ago
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    no i can't sorry

  4. pooja195
    • one year ago
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    I'm not sure what the question is asking.... @zzr0ck3r ??

  5. anonymous
    • one year ago
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    y+8x= 2x squared +1

  6. anonymous
    • one year ago
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    y+8x= 2x squared +1 solve using complete the square

  7. pooja195
    • one year ago
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    y+8x= 2x^1?

  8. anonymous
    • one year ago
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    y+8x= 2x^2 +1?

  9. pooja195
    • one year ago
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    is that the question?

  10. anonymous
    • one year ago
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    yes

  11. pooja195
    • one year ago
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    @zzr0ck3r im not sure can u help with this one please? :)

  12. Astrophysics
    • one year ago
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    \[y=2x^2-8x+1\] now you may go ahead and complete the square

  13. anonymous
    • one year ago
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    i got x^2 -8x+32=15 not sure how to factor that

  14. Astrophysics
    • one year ago
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    \[x^2+ax=0\] we can do the following \[x^2+\frac{ 2ax }{ 2 } + \left( \frac{ a }{ 2 } \right)^2-\left( \frac{ a }{ 2 } \right)^2=0\]

  15. Astrophysics
    • one year ago
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    That's completing the square

  16. anonymous
    • one year ago
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    how do we get the x values

  17. Astrophysics
    • one year ago
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    |dw:1442277314632:dw|

  18. Astrophysics
    • one year ago
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    The -8 and +1 were originally inside the brackets so when we take it out we have to multiply by 2, you can finish it off, by factoring what's inside the parenthesis

  19. Astrophysics
    • one year ago
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    I don't know how you got that

  20. anonymous
    • one year ago
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    I am confused on what to do next

  21. anonymous
    • one year ago
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    2(x-2)^2=-7

  22. Astrophysics
    • one year ago
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    It should = y+7 not -7

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spraguer (Moderator)
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