y+8x= 2x squared +1 solve using complete square

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y+8x= 2x squared +1 solve using complete square

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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no i can't sorry

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I'm not sure what the question is asking.... @zzr0ck3r ??
y+8x= 2x squared +1
y+8x= 2x squared +1 solve using complete the square
y+8x= 2x^1?
y+8x= 2x^2 +1?
is that the question?
yes
@zzr0ck3r im not sure can u help with this one please? :)
\[y=2x^2-8x+1\] now you may go ahead and complete the square
i got x^2 -8x+32=15 not sure how to factor that
\[x^2+ax=0\] we can do the following \[x^2+\frac{ 2ax }{ 2 } + \left( \frac{ a }{ 2 } \right)^2-\left( \frac{ a }{ 2 } \right)^2=0\]
That's completing the square
how do we get the x values
|dw:1442277314632:dw|
The -8 and +1 were originally inside the brackets so when we take it out we have to multiply by 2, you can finish it off, by factoring what's inside the parenthesis
I don't know how you got that
I am confused on what to do next
2(x-2)^2=-7
It should = y+7 not -7

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