f(x)= Solve for Vertical and horizontal Asymptote:
x^2+2x+1 / 2x^2-x-3

f(x)= Solve for Vertical and horizontal Asymptote:
x^2+2x+1 / 2x^2-x-3

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Yeah X+1 cancels. I worked out the problem I just want to see if I did it correctly.

ok so that means there is a hole at x=-1
what was the other factor in the denominator?

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