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anonymous

  • one year ago

2-5i/3i

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  1. anonymous
    • one year ago
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    \[\frac{ 2-5i }{ 3i }\]

  2. anonymous
    • one year ago
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    I understand you are supposed to multiply by the conjugate, but what is the conjugate of 3i

  3. anonymous
    • one year ago
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    @Hero @nincompoop

  4. zepdrix
    • one year ago
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    The conjugate of \(\large\rm 0+3i\) is \(\large\rm 0-3i\)

  5. zepdrix
    • one year ago
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    So therefore the conjugate of \(\large\rm 3i\) is simply \(\large\rm -3i\) k? :)

  6. anonymous
    • one year ago
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    don't be a slave to method you can multiply by \(i\) top and bottom if you like or \(-i\)

  7. zepdrix
    • one year ago
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    Ya that'll save you a couple steps :D Seems like a good idea

  8. anonymous
    • one year ago
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    either way the denominator will become a real number, either 3 or -3 depending on which you pick

  9. anonymous
    • one year ago
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    I see thank you so much

  10. anonymous
    • one year ago
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    Wait, I get a different answer from when i multiply -3i to when i multiply from just i

  11. anonymous
    • one year ago
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    not after you cancel the common factor of 3

  12. anonymous
    • one year ago
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    which is why multiplying by \(-3i\) is silly in this case

  13. anonymous
    • one year ago
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    ohhh so should the final answer be -2i -5

  14. anonymous
    • one year ago
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    idk i didn't do it want me to check?

  15. anonymous
    • one year ago
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    yes please

  16. anonymous
    • one year ago
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    no actually that can't be it

  17. anonymous
    • one year ago
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    \[\frac{ 2-5i }{ 3i }\times \frac{i}{i}\] \[=\frac{2i+5}{-3}\]

  18. anonymous
    • one year ago
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    i got -6i -15 but then factored out 3

  19. anonymous
    • one year ago
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    yes but my answer has to be in complex number form i'm sorry i forgot to mention that

  20. anonymous
    • one year ago
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    now i am confused @satellite73 @zepdrix

  21. anonymous
    • one year ago
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    you mean in the form \(a+bi\)?

  22. anonymous
    • one year ago
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    yes

  23. anonymous
    • one year ago
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    break it in to two pieces is all

  24. anonymous
    • one year ago
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    for example \[\frac{7+8i}{5}=\frac{7}{5}+\frac{8}{5}i\]

  25. anonymous
    • one year ago
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    oh i understand now can i get back to you in a minute with my answer?

  26. anonymous
    • one year ago
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    is this correct? \[\frac{ 2i }{ -3 }+\frac{ 5 }{ -3 }\]

  27. beginnersmind
    • one year ago
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    Yes, although you might want to write it as \[-\frac{ 5 }{ 3 } -\frac{ 2 }{ 3 }i\] or even \[\frac{ -5-2i }{ 3 }\] but it's just cosmetical at this point.

  28. anonymous
    • one year ago
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    thank you so much

  29. beginnersmind
    • one year ago
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    No problem, satellite did all the work though. ;)

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