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anonymous
 one year ago
25i/3i
anonymous
 one year ago
25i/3i

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 25i }{ 3i }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand you are supposed to multiply by the conjugate, but what is the conjugate of 3i

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1The conjugate of \(\large\rm 0+3i\) is \(\large\rm 03i\)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So therefore the conjugate of \(\large\rm 3i\) is simply \(\large\rm 3i\) k? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0don't be a slave to method you can multiply by \(i\) top and bottom if you like or \(i\)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Ya that'll save you a couple steps :D Seems like a good idea

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0either way the denominator will become a real number, either 3 or 3 depending on which you pick

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see thank you so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, I get a different answer from when i multiply 3i to when i multiply from just i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not after you cancel the common factor of 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which is why multiplying by \(3i\) is silly in this case

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh so should the final answer be 2i 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk i didn't do it want me to check?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no actually that can't be it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 25i }{ 3i }\times \frac{i}{i}\] \[=\frac{2i+5}{3}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got 6i 15 but then factored out 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes but my answer has to be in complex number form i'm sorry i forgot to mention that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now i am confused @satellite73 @zepdrix

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you mean in the form \(a+bi\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0break it in to two pieces is all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for example \[\frac{7+8i}{5}=\frac{7}{5}+\frac{8}{5}i\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh i understand now can i get back to you in a minute with my answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is this correct? \[\frac{ 2i }{ 3 }+\frac{ 5 }{ 3 }\]

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.0Yes, although you might want to write it as \[\frac{ 5 }{ 3 } \frac{ 2 }{ 3 }i\] or even \[\frac{ 52i }{ 3 }\] but it's just cosmetical at this point.

beginnersmind
 one year ago
Best ResponseYou've already chosen the best response.0No problem, satellite did all the work though. ;)
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