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anonymous

  • one year ago

Find the point (0, b) on the y-axis that is equidistant from the points (4, 4) and (4, -3).

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  1. freckles
    • one year ago
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    so you have an equation you want the distance from (0,b) to (4,4) to be the same as the distance from (0,b) to (4,-3)

  2. freckles
    • one year ago
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    use distance formula twice once for both sets of points then equate and solve for b

  3. anonymous
    • one year ago
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    well I got -1/14, but its saying its wrong

  4. freckles
    • one year ago
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    so can I ask what equation you solved? did you solve the one I asked you to?

  5. anonymous
    • one year ago
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    yes I used two distance formula for (0,b)(4,4) and (0,b)(4,-3) and i got 24-8b+b^2=25+6b+b^2 which i got 1/14

  6. freckles
    • one year ago
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    \[\sqrt{(0-4)^2+(b-4)^2}=\sqrt{(0-4)^2+(b-(-3))^2} \\ \\ \text{ square both sides } \\ (0-4)^2+(b-4)^2=(0-4)^2+(b-(-3))^2\] now 0-4 is -4 and (-4)^2 =16 also b-(-3) is the same as b+3 so you have: \[16+(b-4)^2=16+(b+3)^2 \\ \text{ subtract 16 on both sides } (b-4)^2=(b+3)^2\] is this what you try to solve ?

  7. freckles
    • one year ago
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    this means you either have b-4=b+3 or b-4=-(b+3) see which one of these equations gives you a solution

  8. freckles
    • one year ago
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    I'm gonna check on my croissant dough unless you have a question

  9. anonymous
    • one year ago
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    im just trying it out to see, i think ill be fine

  10. freckles
    • one year ago
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    ok well I will be back in a few if not

  11. anonymous
    • one year ago
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    ah i got it, thank you so much

  12. freckles
    • one year ago
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    awesome

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