## clara1223 one year ago find the limit as x approaches 9pi/4 of (cos(x)-1)/6x

1. clara1223

$\lim_{x \rightarrow \frac{ 9\pi }{ 4 }}\frac{ \cos(x)-1 }{ 6x }$

2. anonymous

substitute

3. thomas5267

$\lim_{x\to0}\frac{\cos(x)-1}{x}=0$

4. zzr0ck3r

it is defined on a continuous function :)

5. freckles

what is that one commercial that says plug it in plug it in

6. clara1223

@freckles @satellite73 Alright plugging it in I get $\frac{ \cos(\frac{ 9\pi }{ 4 })-1 }{ 6\frac{ 9\pi }{ 4 } }$ $\frac{ \frac{ \sqrt{2} }{ 2 }-\frac{ 2 }{ 2 } }{ \frac{ 54\pi }{ 4 } }$ $\frac{ \sqrt{2}-2 }{ 2 }\times \frac{ 4 }{ 54\pi }$ $\frac{ 4(\sqrt{2}-2) }{ 108\pi }$ $\frac{ \sqrt{2}-2 }{ 27\pi }$ Is there any way to simplify it further?

7. clara1223

8. myininaya

9. myininaya

looks totally awesome!

10. clara1223

Great! thanks so much!