Okay now I have no clue how to solve this one.
Rewrite the equation in Ax+By=C form.
Use integers for A,B,C

- anonymous

- katieb

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- anonymous

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- anonymous

arh...

- anonymous

no biggie
clear the fraction by multiplying EVERYTHING by 2

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## More answers

- anonymous

Right, So how exactly? Do you make 1/2 to just 2?

- anonymous

- anonymous

no dear \(2\times (-\frac{1}{2})=-1\)

- anonymous

but don't forget to multiply all by 2
all the way across
left hand side and right hand side,each term

- anonymous

Oh. okay let me try to solve it :)

- anonymous

kk

- anonymous

|dw:1442282234913:dw|

- anonymous

Right?

- anonymous

yesh...

- anonymous

wait im completely confused

- anonymous

lets go slow again
you want to get rid of the fraction right? so that the coefficients are "integers"

- anonymous

right

- anonymous

you got
\[y=-\frac{1}{2}x-3\]

- anonymous

to get rid of the two in the denominator, multiply both sides by \(2\)
\[2\times y=2\times (-\frac{1}{2}x-3)\]

- anonymous

distribute on the right hand side

- anonymous

2y=-1x-3

- anonymous

hmm looks like you forgot the distributive property
you also have to multiply \(-3\) by \(2\)

- anonymous

ohh so 2y=-1x-6

- anonymous

correct?

- anonymous

yes

- anonymous

now add \(x\) to both sides and you are done

- anonymous

1x+2y=6

- anonymous

yeah but drop the \(1\) or your teacher will think you are daft

- anonymous

so just x+2y=6

- anonymous

damn, dropped the minus sign again on the right didn't you?

- anonymous

x-2y=6???

- anonymous

a common mistake actually
now on the right, it was \(-6\) so it is still \(-6\)

- anonymous

\[x+2y=-6\] in other words

- anonymous

Oh, well thanks.

- anonymous

yw

- anonymous

Im no math genius as you can tell

- anonymous

lol that is fine, that is why you are doing homework, to learn it !

- anonymous

I suppose lol. Thanks for making me feel better

- anonymous

yw ( you will "get it" as they say)

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