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clara1223

  • one year ago

Given that f(x)={8+x^3 when x<=1 and Bx+C when x>1} Determine the values of the constants B and C so that f is differentiable.

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  1. anonymous
    • one year ago
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    first plug in 1 to both what do you get?

  2. clara1223
    • one year ago
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    I get 9 and B+C

  3. anonymous
    • one year ago
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    ok so you have one equation \[B+C=9\] now take the derivative of both and then plug in 1

  4. anonymous
    • one year ago
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    did i lose you there?

  5. clara1223
    • one year ago
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    sorry I had to restart my computer, it was being weird. But using the shortcut I get that both derivatives are 0 because there are no xs

  6. clara1223
    • one year ago
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    how do you find a derivative if there is no x?

  7. anonymous
    • one year ago
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    there is an \(x\) in \(Bx+C\) for sure

  8. clara1223
    • one year ago
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    oh you mean before i plugged in 1, gotcha.

  9. anonymous
    • one year ago
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    oh yes before

  10. clara1223
    • one year ago
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    what do i do after I get the derivative and plug in 1? I need to go do something before i finish this problem but im guessing you wont be online later so i was hoping you could explain really quickly so i will know how to do it later.

  11. anonymous
    • one year ago
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    yes plug in 1 to both you should get \[B=3\]

  12. anonymous
    • one year ago
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    making \(A=6\) and you are done

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