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y=mx+b For two lines to be perpendicular, their two slopes (m) must be -1 when it gets multiplied. y=2x-3 2 represemts m in y=mx+b, so the slope is 2 2*(slope of other line)=-1
Y=(slope)x+y-intercept thats why
Okay so, y = 3x – 3 the slope would be 1/3?
no its just 3
Slope of which line? y=3x-3 or the line perpendicular to y=3x-3? Btw dont listen to the person that posted after me. It is not correct.
take the original slope flip the fraction and flip the sign to get the perpendicular slope
so for example, if we had the original slope to be 2/7, then the perpendicular slope would be -7/2 another example original: -4/9 perpendicular: 9/4 these are just examples and none of this is the answer
wait. it wants the parallel to y = 3x - 3
parallel lines have equal slopes
How are you skipping to another equation and going from perpendicular to parallel? Are you done with your first question?
okay so it'd be three
the slope of the first one, the perpendicular thing, would be -2 since apparently it's the opposite of the original.
sloppycanada, you forgot to flip the fraction
think of 2 as 2/1
So it'd be -1/2? Since it's positive in the original?
yeah if +2/1 is the original slope, then -1/2 is the perpendicular slope
What is the slope of the line that is parallel to y = 3x – 3? so for this it'd just be 3?
Thanks a bunch!