I need help will fan+medal?!?!?!?!

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I need help will fan+medal?!?!?!?!

Mathematics
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simplify \[\sqrt[3]{7}/\sqrt[5]{7}\]
A. 7 to the power of 1 over 5 B. 7 to the power of 8 over 15 C. 7 to the power of 5 over 3 D. 7 to the power of 2 over 15
@Nasa7 CAN U HELP PLZ

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Other answers:

@rock_mit182 do u know how to simplify this?
first question would be 1 because they are both the same and when you divide them together it would be 1
i need it simplified though not the answer
|dw:1442284199542:dw|
@Queli what did you get ?
Im not sure..
keep in mind in our case: a = 7
ill help you out with the numerator
\[7^{2/3}\] and \[7^{2/5}\]
|dw:1442284606506:dw|
you were close enough, try again. keep in mind what i told you about : \[7 = 7^{1}\]
\[7^{1/3} and 7^{1/5}\] so the answer would be d right
\[\frac{ 7^{\frac{ 1 }{ 3 }} }{ 7^{\frac{ 1 }{ 5 }} } = 7 ^{\frac{ 1 }{ 3 }}* 7\frac{- 1 }{ 5 }\]
WHisch is the same as: \[=7^{\frac{ 1 }{ 3 }-\frac{ 1 }{ 5 }}\]
can you solve this by your own now ?
1/3 - 1/5 ?
7 to the power of .... ?
the common denominator would be 15 so 5/15-3/15=2/15
yeah :)
nice work
that's all my friend
thanks been stuck on that problem for hrs : )
bu you're smart enough to figure out anything. you're welcome

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