anonymous
  • anonymous
Use left and right endpoints and the given number of rectangles to find two approximations of the area of the region between the graph of the function and the x-axis over the given interval. g(x) = 2x2 − x − 1, [3, 5], 4 rectangles
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
how far did you get?
anonymous
  • anonymous
I got it wrong :/
jim_thompson5910
  • jim_thompson5910
can you show me what steps you have so I can see where you went wrong

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anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
how did you get the `5+6+7+8` ?
anonymous
  • anonymous
that's what it told me to do in the problem before
anonymous
  • anonymous
it's a sum
jim_thompson5910
  • jim_thompson5910
maybe you were thinking of f(3) + f(3.5) + ... ??
anonymous
  • anonymous
should it be?
jim_thompson5910
  • jim_thompson5910
let's draw out the graph
jim_thompson5910
  • jim_thompson5910
|dw:1442286116197:dw|
jim_thompson5910
  • jim_thompson5910
here is f(x) |dw:1442286125598:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1442286156489:dw|
jim_thompson5910
  • jim_thompson5910
divide the interval from 3 to 5 into four pieces |dw:1442286172862:dw|
jim_thompson5910
  • jim_thompson5910
the left rectangle approximation will look like this |dw:1442286205016:dw|
jim_thompson5910
  • jim_thompson5910
agreed so far?
anonymous
  • anonymous
yes!
jim_thompson5910
  • jim_thompson5910
ok so you have the delta x part correct that is delta x = (b-a)/n delta x = (5-3)/4 delta x = 2/4 delta x = 1/2 delta x = 0.5 this is the width of each rectangle |dw:1442286351913:dw|
anonymous
  • anonymous
yes!
jim_thompson5910
  • jim_thompson5910
you can factor out the delta x terms which is what you have on your paper the heights of each rectangle is based on f(x) the first rectangle has a height of f(3) |dw:1442286417246:dw|