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iwanttogotostanford

  • one year ago

PLEASE HELP URGENT: For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range.

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  1. iwanttogotostanford
    • one year ago
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    @mathway @myininaya @CloverRacer @l

  2. iwanttogotostanford
    • one year ago
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    @shelby1290 @Bee_see @wolf1728

  3. iwanttogotostanford
    • one year ago
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    @vera_ewing

  4. wolf1728
    • one year ago
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    Would that be: f(x) = 3*(x − 1)*(x − 1) + 2 ?

  5. iwanttogotostanford
    • one year ago
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    yes

  6. iwanttogotostanford
    • one year ago
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    well it i this; f(x) = 3(x − 1)^2 + 2 sorry

  7. sleepyhead314
    • one year ago
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    The vertex form of a parabola is given as \( y = a (x-h)^2 + k \) where the point \( (h,k) \) is the vertex so comparing the two: \(y=3(x-1)^2 +2\) and \(y=a(x-h)^2+k\) can you tell me what you think the vertex is? :)

  8. iwanttogotostanford
    • one year ago
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    the first one?

  9. wolf1728
    • one year ago
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    Hmm, it seems sleepyhead is trying another approach, I multiplied it out: f(x) = 3*(x − 1)*(x − 1) + 2 equals 3 * x^2 -2x +1 +2 equals 3 x^2 -2x +3

  10. sleepyhead314
    • one year ago
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    I mean as a point :P or tell me h = k = that's ok too

  11. sleepyhead314
    • one year ago
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    yes, as it asks for the vertex - I assumed it would be easier to point it out since it is already in "vertex form" @wolf1728 :)

  12. iwanttogotostanford
    • one year ago
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    these are my choices: The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≤ 2.

  13. sleepyhead314
    • one year ago
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    then yes, your guess is correct! @iwanttogotostanford Good Job! :)

  14. iwanttogotostanford
    • one year ago
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    so it would be A?:_)

  15. sleepyhead314
    • one year ago
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    indeed ^_^

  16. iwanttogotostanford
    • one year ago
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    WAIT I HAVE ANOTHER QUSTION DONT LEAVE

  17. iwanttogotostanford
    • one year ago
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    thank you WAIT CAN I ASK ANOTHER PLEASE

  18. iwanttogotostanford
    • one year ago
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    Given the functions f(x) = 3x2, g(x) = x2 − 4x + 5, and h(x) = –2x2 + 4x + 1, rank them from least to greatest based on their axis of symmetry.

  19. iwanttogotostanford
    • one year ago
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    these are my choices:-) thanks for the help f(x), g(x), h(x) f(x), h(x), g(x) g(x), h(x), f(x) g(x), f(x), h(x)

  20. sleepyhead314
    • one year ago
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    the axis of symmetry is given by \( \large x = \frac{-b}{2a}\) when the equations are in a form \(y=ax^2+bx+c\)

  21. iwanttogotostanford
    • one year ago
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    so it would be c? @sleepyhead314

  22. sleepyhead314
    • one year ago
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    yes :) that's what I got too! you're doing great ^_^

  23. iwanttogotostanford
    • one year ago
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    thank you! one more?? sorry.... @wolf1728 @sleepyhead314

  24. iwanttogotostanford
    • one year ago
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    Given the function f(x) = x2 and k = –1, which of the following represents a function opening downward? Answer choices: f(x) + k kf(x) f(x + k) f(kx)

  25. sleepyhead314
    • one year ago
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    perhaps consider making a new question so that we don't both wolf too much with the notifications :)

  26. iwanttogotostanford
    • one year ago
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    okay i will!

  27. wolf1728
    • one year ago
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    I made a mistake on previous problem f(x) = 3*(x − 1)*(x − 1) + 2 equals 3 * (x^2 -2x +1) +2 equals 3 x^2 -6x +5

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