iwanttogotostanford
  • iwanttogotostanford
PLEASE HELP URGENT: For the function f(x) = 3(x − 1)2 + 2, identify the vertex, domain, and range.
Mathematics
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SOLVED
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chestercat
  • chestercat
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iwanttogotostanford
  • iwanttogotostanford
@mathway @myininaya @CloverRacer @l
iwanttogotostanford
  • iwanttogotostanford
@shelby1290 @Bee_see @wolf1728
iwanttogotostanford
  • iwanttogotostanford
@vera_ewing

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More answers

wolf1728
  • wolf1728
Would that be: f(x) = 3*(x − 1)*(x − 1) + 2 ?
iwanttogotostanford
  • iwanttogotostanford
yes
iwanttogotostanford
  • iwanttogotostanford
well it i this; f(x) = 3(x − 1)^2 + 2 sorry
sleepyhead314
  • sleepyhead314
The vertex form of a parabola is given as \( y = a (x-h)^2 + k \) where the point \( (h,k) \) is the vertex so comparing the two: \(y=3(x-1)^2 +2\) and \(y=a(x-h)^2+k\) can you tell me what you think the vertex is? :)
iwanttogotostanford
  • iwanttogotostanford
the first one?
wolf1728
  • wolf1728
Hmm, it seems sleepyhead is trying another approach, I multiplied it out: f(x) = 3*(x − 1)*(x − 1) + 2 equals 3 * x^2 -2x +1 +2 equals 3 x^2 -2x +3
sleepyhead314
  • sleepyhead314
I mean as a point :P or tell me h = k = that's ok too
sleepyhead314
  • sleepyhead314
yes, as it asks for the vertex - I assumed it would be easier to point it out since it is already in "vertex form" @wolf1728 :)
iwanttogotostanford
  • iwanttogotostanford
these are my choices: The vertex is (1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (1, 2), the domain is all real numbers, and the range is y ≤ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≥ 2. The vertex is (–1, 2), the domain is all real numbers, and the range is y ≤ 2.
sleepyhead314
  • sleepyhead314
then yes, your guess is correct! @iwanttogotostanford Good Job! :)
iwanttogotostanford
  • iwanttogotostanford
so it would be A?:_)
sleepyhead314
  • sleepyhead314
indeed ^_^
iwanttogotostanford
  • iwanttogotostanford
WAIT I HAVE ANOTHER QUSTION DONT LEAVE
iwanttogotostanford
  • iwanttogotostanford
thank you WAIT CAN I ASK ANOTHER PLEASE
iwanttogotostanford
  • iwanttogotostanford
Given the functions f(x) = 3x2, g(x) = x2 − 4x + 5, and h(x) = –2x2 + 4x + 1, rank them from least to greatest based on their axis of symmetry.
iwanttogotostanford
  • iwanttogotostanford
these are my choices:-) thanks for the help f(x), g(x), h(x) f(x), h(x), g(x) g(x), h(x), f(x) g(x), f(x), h(x)
sleepyhead314
  • sleepyhead314
the axis of symmetry is given by \( \large x = \frac{-b}{2a}\) when the equations are in a form \(y=ax^2+bx+c\)
iwanttogotostanford
  • iwanttogotostanford
so it would be c? @sleepyhead314
sleepyhead314
  • sleepyhead314
yes :) that's what I got too! you're doing great ^_^
iwanttogotostanford
  • iwanttogotostanford
thank you! one more?? sorry.... @wolf1728 @sleepyhead314
iwanttogotostanford
  • iwanttogotostanford
Given the function f(x) = x2 and k = –1, which of the following represents a function opening downward? Answer choices: f(x) + k kf(x) f(x + k) f(kx)
sleepyhead314
  • sleepyhead314
perhaps consider making a new question so that we don't both wolf too much with the notifications :)
iwanttogotostanford
  • iwanttogotostanford
okay i will!
wolf1728
  • wolf1728
I made a mistake on previous problem f(x) = 3*(x − 1)*(x − 1) + 2 equals 3 * (x^2 -2x +1) +2 equals 3 x^2 -6x +5

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