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iwanttogotostanford

  • one year ago

What is the equation of the following graph in vertex form? parabolic function going down from the left through the point zero comma twelve and through the point two comma zero and turning at the point four comma negative four and going up through the point six comma zero and continuing towards infinity

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  1. iwanttogotostanford
    • one year ago
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    @wolf1728 @sleepyhead314

  2. sleepyhead314
    • one year ago
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    I will assume that the "turning point" would be the vertex

  3. sleepyhead314
    • one year ago
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    vertex form is: \(y=a(x-h)^2+k\) where \((h,k)\) is the vertex point and I forgot how to find a >,<

  4. iwanttogotostanford
    • one year ago
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    heres the pic of the graph

  5. iwanttogotostanford
    • one year ago
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    sorry can't get the pic

  6. iwanttogotostanford
    • one year ago
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    here are the answer choices though: y = (x − 4)2 − 4 y = (x + 4)2 − 4 y = (x + 2)2 + 6 y = (x + 2)2 + 12

  7. campbell_st
    • one year ago
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    well you know the vertex is (4, -4) so the equation is \[y = a(x -4)^2 - 4\] to find the value of a, substitute any point on the curve, other than the vertex, into the equation to find a

  8. iwanttogotostanford
    • one year ago
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    so it would be B?

  9. iwanttogotostanford
    • one year ago
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    help please guys @sleepyhead314 @wolf1728

  10. sleepyhead314
    • one year ago
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    take a look at what campbell_st wrote :)

  11. iwanttogotostanford
    • one year ago
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    i need the answer i still have to study for a test and i just need help please @sleepyhead314

  12. sleepyhead314
    • one year ago
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    campbell has showed clearly what your answer should be :)

  13. wolf1728
    • one year ago
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    campbell said the equation is y=a(x−4)^2−4

  14. iwanttogotostanford
    • one year ago
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    thank you guys, sorry a bit tired here

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