iwanttogotostanford
  • iwanttogotostanford
What is the equation of the following graph in vertex form? parabolic function going down from the left through the point zero comma twelve and through the point two comma zero and turning at the point four comma negative four and going up through the point six comma zero and continuing towards infinity
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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iwanttogotostanford
  • iwanttogotostanford
@wolf1728 @sleepyhead314
sleepyhead314
  • sleepyhead314
I will assume that the "turning point" would be the vertex
sleepyhead314
  • sleepyhead314
vertex form is: \(y=a(x-h)^2+k\) where \((h,k)\) is the vertex point and I forgot how to find a >,<

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iwanttogotostanford
  • iwanttogotostanford
heres the pic of the graph
iwanttogotostanford
  • iwanttogotostanford
sorry can't get the pic
iwanttogotostanford
  • iwanttogotostanford
here are the answer choices though: y = (x − 4)2 − 4 y = (x + 4)2 − 4 y = (x + 2)2 + 6 y = (x + 2)2 + 12
campbell_st
  • campbell_st
well you know the vertex is (4, -4) so the equation is \[y = a(x -4)^2 - 4\] to find the value of a, substitute any point on the curve, other than the vertex, into the equation to find a
iwanttogotostanford
  • iwanttogotostanford
so it would be B?
iwanttogotostanford
  • iwanttogotostanford
help please guys @sleepyhead314 @wolf1728
sleepyhead314
  • sleepyhead314
take a look at what campbell_st wrote :)
iwanttogotostanford
  • iwanttogotostanford
i need the answer i still have to study for a test and i just need help please @sleepyhead314
sleepyhead314
  • sleepyhead314
campbell has showed clearly what your answer should be :)
wolf1728
  • wolf1728
campbell said the equation is y=a(x−4)^2−4
iwanttogotostanford
  • iwanttogotostanford
thank you guys, sorry a bit tired here

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