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anonymous
 one year ago
Find the center (h, k) and the radius r of the circle
2 x^2  6 x +2 y^2 + 9 y  3 = 0 .
anonymous
 one year ago
Find the center (h, k) and the radius r of the circle 2 x^2  6 x +2 y^2 + 9 y  3 = 0 .

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zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1You need to complete the square twice. I will do one of them, \[2 x^2  6 x +2 y^2 + 9 y  3 = 0\\2x^26x+2y^2+9y=3\\2(x^2+3x)+2y^2+9y=3\\2(x+\frac{3}{2})^2+2y^2+9y=3+2(\frac{3}{2})^2\]

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1Equation of a circle is \[(xh)^2+(yk)^2=r^2\] Where \((h,k)\) is the center and \(r\) is the radius. Yuu have to complete the square twice. \[2 x^2  6 x +2 y^2 + 9 y  3 = 0 \\2x^26x+2y^2+9y=3 \\2(x^23x)+2(y^2+\frac{9}{2}y)=3 \\2(x\frac{3}{2})^2+2(y+\frac{9}{4})^2=3+2(\frac{3}{2})^2+2(\frac{9}{4})^2=\frac{141}{8}\\\\(x\frac{3}{2})^2+(y+\frac{9}{4})^2=\frac{141}{16}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh okay that makes a lot of sense..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, ive tried it again but for radius i got 117/8. I tried to enter both but none of the radius were right @zzr0ck3r

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1The radius would be, according to the formula, \(r=\sqrt{\frac{141}{16}}=\frac{\sqrt{141}}{4}\).
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