steve816
  • steve816
The density of a substance is 570 mg/mL. What is its density in kg/L?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ganeshie8
  • ganeshie8
Hint : \(1 mg = 10^{-3}g\) \(1mL = 10^{-3}L\)
jim_thompson5910
  • jim_thompson5910
it might be easier to use 1000 mg = 1 g 1000 mL = 1 L that's just my opinion though
steve816
  • steve816
Hmmm, I got .000570 kg/L Is that correct?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
This is one way to set up \[\Large \frac{570 \text{ mg}}{1 \text{ mL}} \times \frac{1000 \text{ mL}}{1 \text{ L}} \times \frac{1 \text{ g}}{1000 \text{ mg}} \]
jim_thompson5910
  • jim_thompson5910
oh wait, you want kg not g, let me fix
jim_thompson5910
  • jim_thompson5910
1000 mg = 1 g 1000 mL = 1 L 1000 g = 1 kg \[\Large \frac{570 \text{ mg}}{1 \text{ mL}} \times \frac{1000 \text{ mL}}{1 \text{ L}} \times \frac{1 \text{ g}}{1000 \text{ mg}} \times \frac{1 \text{ kg}}{1000 \text{ g}} \]
jim_thompson5910
  • jim_thompson5910
0.000570 kg/L is not correct
steve816
  • steve816
I think I figured this out! Thank you jim, very helpful :)
jim_thompson5910
  • jim_thompson5910
glad it's making sense now

Looking for something else?

Not the answer you are looking for? Search for more explanations.