Aliza29faye
  • Aliza29faye
A 200 lb box is setting on an inclined plane which has an angle of 30 degrees. The coefficient of static friction in this case is 0.3. a) What is the force acting normal to the surface of the plane? b) What is the component of the force of gravity acting down the plane? c) What is the maximum friction force acting to keep the box from moving? d) What force is needed to start the box moving up the plane? e) What force is needed to start the box moving down the plane? diagram in comments
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Aliza29faye
  • Aliza29faye
|dw:1442300095807:dw|
anonymous
  • anonymous
a) here , for the equilibrium of the block let the force normal to surface is N N = W * cos(30) N = 200 * cos(30) N = 173.2 lb the force acting normal to surface is 173.2 lbf b) component of gravity down the plane = W * sin(30) component of gravity down the plane = 200 * sin(30) component of gravity down the plane = 100 lbf the component of gravity down the plane is 100 lbf c) maximum friction force = u * N maximum friction force = 0.30 * 173.2 maximum friction force = 52 lbf the maximum friction force is 52 lbf d) let the force needed is F for the block to move upwards F - W * sin(30) - friction force = 0 F - 100 - 52 = 0 F = 152 lbf the minimum force needed to move the block up the plane is 152 lbf e) for the block to move downwards as gravity component down the plane is greater than friction the block will start moving downwards with out any force
Aliza29faye
  • Aliza29faye
Thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.