Diana.xL
  • Diana.xL
Help!
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Diana.xL
  • Diana.xL
http://prntscr.com/8gix28
Diana.xL
  • Diana.xL
plz help! i need a step by step explanation
imqwerty
  • imqwerty
the area of a rectangle is given by= length x breadth you are given - \[area=x^2 +12x\]and \[breadth=x\] let the length be l so \[l \times x =x^2 +12x\] then u take x common in the right hand side \[l \times x =x(x+12)\]then divide both sides by x\[(l \times x)\div x =x(x+12)\div x\]\[l=x+12 \]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Diana.xL
  • Diana.xL
Thank u soo much! can u help me with part b?
Diana.xL
  • Diana.xL
http://prntscr.com/8gj1og
imqwerty
  • imqwerty
so in part b u just have u find the numeric value of l and this time u are given that x=10 up there^ we found out that l=x+12 so jst put x=10 and get- l=10+12 l=22
Diana.xL
  • Diana.xL
thats all we have to do?
imqwerty
  • imqwerty
yes :)
Diana.xL
  • Diana.xL
Thank u! :))
imqwerty
  • imqwerty
no prblm :D btw sry i replied so late i was chattin down there in the chat boxes :)
Diana.xL
  • Diana.xL
its ok :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.