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mathmath333

  • one year ago

Their are 4 letters and 4 envelopes.find the number of ways in which only two letters go in wrong envelope ?

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{Their are 4 letters and 4 envelopes.find the number of ways }\hspace{.33em}\\~\\ & \normalsize \text{in which only two letters go in wrong envelope ?}\hspace{.33em}\\~\\ & a.)\ 4 \hspace{.33em}\\~\\ & b.)\ 5 \hspace{.33em}\\~\\ & c.)\ 6 \hspace{.33em}\\~\\ & d.)\ 3 \hspace{.33em}\\~\\ \end{align}}\)

  2. anonymous
    • one year ago
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    its c 6 ways

  3. mathmath333
    • one year ago
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    yea how u got it

  4. anonymous
    • one year ago
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    we will need to select the two letters which have to be put in wrong envelop . that is \[4 \times \frac{ 3 }{ 2 }\] i.e \[^{4}c _{2} = 6\]

  5. mathmath333
    • one year ago
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    thnks

  6. anonymous
    • one year ago
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    no worries :)

  7. anonymous
    • one year ago
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    Yep :) It's C, 6 ways :)

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