A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
What is the difference in the total number of factors and the number of prime factors in 60^3  32^3  28^3
anonymous
 one year ago
What is the difference in the total number of factors and the number of prime factors in 60^3  32^3  28^3

This Question is Closed

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(60^{3} 32^{3}  28^{3} =3\times 32\times 28\times 60\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0options : 1) 116 2) 120 3) 126 4) 130

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Start with : \(6032=28\) cube both sides \((6032)^3 = 28^3\) For left hand side, recall the identity \((ab)^3 = a^3b^33ab(ab)\) : \(60^332^3 3\cdot 60\cdot 32(6032) = 28^3\) \(\implies 60^332^328^3 = 3\cdot 60\cdot 32\cdot 28=2^9\cdot 3^2\cdot 5\cdot 7\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2so thats the prime factorization do you know how to find the number of factors of a number from prime factorization ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2good, see if you can finish the rest
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.