anonymous
  • anonymous
Find the area of a sector with a central angle of 216 degrees and a radius of 18.4 millimeters and round to the nearest tenth. Help please!
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
do u know formula \[A=\frac{ 1 }{ 2 } r ^{2} \theta \]
anonymous
  • anonymous
No. I missed a day of class and that was the only day my teacher went over that and I have an assignment on it. :(
anonymous
  • anonymous
dont use the formula i gave u its in radians

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Oh okay.
anonymous
  • anonymous
area =\[\pi r ^{2} (\frac{ c }{ 360 })\]
anonymous
  • anonymous
c is the central angle in ur case its 216
anonymous
  • anonymous
\[\pi 18.4^{2} \times \frac{ 216 }{ 360 } =638.1705653 mm ^{2}\]
anonymous
  • anonymous
got it?
anonymous
  • anonymous
So that's the formula I should use?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Awesome, thank you so much!
anonymous
  • anonymous
\[area= \pi r ^{2}\times \frac{ c }{ 360 }\]
anonymous
  • anonymous
no worries :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.