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anonymous
 one year ago
Write the first three therms of the following series.Please help
anonymous
 one year ago
Write the first three therms of the following series.Please help

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Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.2Do you have the series pattern given?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{1}^{\infty} \frac{ 3n  2 }{ n ^{2} + 1 }\]

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.2A series is nothing more than a definable sum of terms, and it usually follows a pattern, and it is written inside the Sigma. \[\sum_{n=1}^{\infty} \frac{ 3n2 }{ n^2+1 }\] we can find any term by limiting the sum to the desired term, in this case, it's 3: \[\sum_{n=1}^{n=3}\frac{ 3n2 }{ n^2+1 }\] And, this just translates to: \[\sum_{n=1}^{n=3}\frac{ 3n2 }{ n^2+1 }=\frac{ 3(1)2 }{ (1)^2+1 }+\frac{ 3(2)2 }{ (2)^2+1 } + \frac{ 3(3)2 }{ (3)^2+1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0srry cant u just take a limit and divide the whole thing with the biggest power which in this case is n^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it right what he jsut said?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am not sure if i am right i am pretty sure he is right

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.2You take the limit when you desire to know if the series is convergent or divergent. When you want to find terms, you replace them on the actual pattern.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got another question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Post it here or make open another topic?

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.2Post it on another topic, so it doesn't get messy.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok srry i didnt read the question about three terms
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