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anonymous
 one year ago
Solve the system of equations using matrices. Use Gaussian elimination with backsubstitution.
x + y + z = 5
x  y + 3z = 1
4x + y + z = 2
anonymous
 one year ago
Solve the system of equations using matrices. Use Gaussian elimination with backsubstitution. x + y + z = 5 x  y + 3z = 1 4x + y + z = 2

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UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1[ 1 1 1 ] [ x ] [5] [ 1 1 3 ] [ y ] = [1] [ 4 1 1 ] [ z ] [2]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yesss ok so what do i do here

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1[ 1 1 1  5] [ 1 1 3 1] [ 4 1 1  2]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1we want make this [ ...........] [ x...... ..] [ ........ ..] element into a zero

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1take away the first row from the second row

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1[ 1 1 1  5] (R1) [ 1 1 3  1] (R2) [ 4 1 1  2] (R3) (R2)(R1) = [(11) (11) (31)  (15)]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whats next or is that it

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1we get [ 1 1 1  5] (R1) [ 0 2 2  6] (R2) [ 4 1 1  2] (R3)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1now we want make this [ 1.........] [ 0...... ..] [ x........ ..] element zero

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1so take away line row 1 from row 3, four times

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1[ 4 1 1  2]  4*[ 1 1 1  5] =

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0umm idk im not good with these i just started this
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