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anonymous
 one year ago
A question about linear algebra.... See attachment please
anonymous
 one year ago
A question about linear algebra.... See attachment please

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My question is...... are there times when you can't express the result as a linear combination of the two others?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If so is what clues you in on that?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Maybe lets try an example in \(xy\) plane first : can you express the vector \((2,2)\) using a linear combination of vectors \((1,0)\) and \((2,0)\) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So when you say the vector (2,2) that would be \[a_{1}=\left(\begin{matrix}2 \\ 2\end{matrix}\right)\] correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok give me a second to try it out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can see it now because both of the "Y" elements are zero then there is no multiple of zero that could combine to equal 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you, is there a method in general (by inspection) that I can use to check one of these before attempting to work the problem out?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1so what do you conclude ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Yes, there is a method. Before getting to that, I just want to see you get the idea of taking linear combinations of vectors..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If all X,Y,Z, or Nth element of each vector is zero and the resultant vector is nonzero I can concluded that there is no linear combination of the vectors that will give the correct resultant vector

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And I am not sure i am getting the idea your referring to

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1I am not referring to any idea yet

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1The present problem is cooked up to be done by visual inspection

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What I meant is you said " I just want to see you get the idea of taking linear combinations of vectors." and honestly I am not sure that I am

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1for part (i), try \(3a_1 + 2a_2\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1for part (ii), try \(3a_1 + 4a_2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I actually found a solution for both....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I was trying to figure out 1) if there was a time this wouldn't work. (which you have shown me) and a way to inspect them and get a definite "NO" sometimes.... if what I am saying makes sense
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