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what are the forces acting on the flower pot during the motion?
you mean the gravity?
Take the free fall acceleration to be 9.80m/s^2 .
yeah gravity is the only force acting here!
by newtons2nd the sum of the forces is equal the mass times its acceleration ∑ F = ma = mg (if we define the y axis pointing downwards ) so a = g
we get y(t) = y_0 + v_y0 t + 1/2 g t^2
hmmm..can you show me how you derived to that equation
the one i know is d=Vit + 1/2at^2
a = y'' = g v = y' = ∫ g dt = gt +c y = ∫ (gt + c) dt = 1/2 gt^2 +c_1t + c_2
y(0) = y_0 --> c_2 = y_0 v(0) = v_y0 --> c_1 = v_y0
ok...how can we solve this ^^ using that formula
y(t_1) = y_0 + v_y0 (t_1) + 1/2 g (t_1)^2 y(t_2) = y_0 + v_y0 (t_2) + 1/2 g (t_2)^2 D = y(t_2) - y(t_1) = v_y0 (t_2-t_1) + 1/2 g (t_2-t_1)^2 is this like your formula?
so D is the displacement? and (t_2 - t_1) is the time it takes of the pot to fall past the window
how much displacement is is this example?
so we have ( v_i = v_y0 ) D = v_i t + 1/2 g t^2 lets solve this equation for v_i, the velocity of the pot plant when it was falling past the top the the window and Then, calculate with D = 1.90 m t = 0.420 s g = 9.80 m/s^2
what do you get when you rearrange the equation ?
is that we only need?
now we have the initial velocity , we still need to work out the height to the window sill
Do you have formulas you can just use, or is the derivation helpful?
hmmm.. idk which formula to use lol
we need to find the distance to the windowsill from the lower window, we have the velocities
do you have a set of 5 equations of projectile motion?
or i suppose we can say the the pot started on the sill at rest, and was falling at 2.4658 m/s, at the top on the next window down how long was it falling ?
we dont learn projectile from now so i really dont know