anonymous
  • anonymous
A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes time 0.420 s to pass this window, which is of height 1.90 m. Question- How far is the top of the window below the windowsill from which the flowerpot fell?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@UnkleRhaukus
anonymous
  • anonymous
@johnweldon1993
UnkleRhaukus
  • UnkleRhaukus
|dw:1442325952193:dw|

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UnkleRhaukus
  • UnkleRhaukus
what are the forces acting on the flower pot during the motion?
anonymous
  • anonymous
you mean the gravity?
anonymous
  • anonymous
Take the free fall acceleration to be 9.80m/s^2 .
UnkleRhaukus
  • UnkleRhaukus
yeah gravity is the only force acting here!
UnkleRhaukus
  • UnkleRhaukus
|dw:1442326446681:dw|
UnkleRhaukus
  • UnkleRhaukus
by newtons2nd the sum of the forces is equal the mass times its acceleration ∑ F = ma = mg (if we define the y axis pointing downwards ) so a = g
UnkleRhaukus
  • UnkleRhaukus
we get y(t) = y_0 + v_y0 t + 1/2 g t^2
anonymous
  • anonymous
hmmm..can you show me how you derived to that equation
anonymous
  • anonymous
the one i know is d=Vit + 1/2at^2
UnkleRhaukus
  • UnkleRhaukus
a = y'' = g v = y' = ∫ g dt = gt +c y = ∫ (gt + c) dt = 1/2 gt^2 +c_1t + c_2
UnkleRhaukus
  • UnkleRhaukus
y(0) = y_0 --> c_2 = y_0 v(0) = v_y0 --> c_1 = v_y0
anonymous
  • anonymous
ok...how can we solve this ^^ using that formula
UnkleRhaukus
  • UnkleRhaukus
y(t_1) = y_0 + v_y0 (t_1) + 1/2 g (t_1)^2 y(t_2) = y_0 + v_y0 (t_2) + 1/2 g (t_2)^2 D = y(t_2) - y(t_1) = v_y0 (t_2-t_1) + 1/2 g (t_2-t_1)^2 is this like your formula?
anonymous
  • anonymous
yup
UnkleRhaukus
  • UnkleRhaukus
so D is the displacement? and (t_2 - t_1) is the time it takes of the pot to fall past the window
anonymous
  • anonymous
absolutely
UnkleRhaukus
  • UnkleRhaukus
how much displacement is is this example?
anonymous
  • anonymous
1.90m
UnkleRhaukus
  • UnkleRhaukus
so we have ( v_i = v_y0 ) D = v_i t + 1/2 g t^2 lets solve this equation for v_i, the velocity of the pot plant when it was falling past the top the the window and Then, calculate with D = 1.90 m t = 0.420 s g = 9.80 m/s^2
UnkleRhaukus
  • UnkleRhaukus
what do you get when you rearrange the equation ?
anonymous
  • anonymous
2.4658
anonymous
  • anonymous
m/s
anonymous
  • anonymous
is that we only need?
UnkleRhaukus
  • UnkleRhaukus
now we have the initial velocity , we still need to work out the height to the window sill
UnkleRhaukus
  • UnkleRhaukus
Do you have formulas you can just use, or is the derivation helpful?
anonymous
  • anonymous
hmmm.. idk which formula to use lol
UnkleRhaukus
  • UnkleRhaukus
we need to find the distance to the windowsill from the lower window, we have the velocities
UnkleRhaukus
  • UnkleRhaukus
do you have a set of 5 equations of projectile motion?
UnkleRhaukus
  • UnkleRhaukus
or i suppose we can say the the pot started on the sill at rest, and was falling at 2.4658 m/s, at the top on the next window down how long was it falling ?
anonymous
  • anonymous
we dont learn projectile from now so i really dont know
anonymous
  • anonymous
@rishavraj

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