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anonymous
 one year ago
A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes time 0.420 s to pass this window, which is of height 1.90 m. Question How far is the top of the window below the windowsill from which the flowerpot fell?
anonymous
 one year ago
A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes time 0.420 s to pass this window, which is of height 1.90 m. Question How far is the top of the window below the windowsill from which the flowerpot fell?

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UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442325952193:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1what are the forces acting on the flower pot during the motion?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you mean the gravity?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Take the free fall acceleration to be 9.80m/s^2 .

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1yeah gravity is the only force acting here!

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442326446681:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1by newtons2nd the sum of the forces is equal the mass times its acceleration ∑ F = ma = mg (if we define the y axis pointing downwards ) so a = g

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1we get y(t) = y_0 + v_y0 t + 1/2 g t^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm..can you show me how you derived to that equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the one i know is d=Vit + 1/2at^2

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1a = y'' = g v = y' = ∫ g dt = gt +c y = ∫ (gt + c) dt = 1/2 gt^2 +c_1t + c_2

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1y(0) = y_0 > c_2 = y_0 v(0) = v_y0 > c_1 = v_y0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok...how can we solve this ^^ using that formula

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1y(t_1) = y_0 + v_y0 (t_1) + 1/2 g (t_1)^2 y(t_2) = y_0 + v_y0 (t_2) + 1/2 g (t_2)^2 D = y(t_2)  y(t_1) = v_y0 (t_2t_1) + 1/2 g (t_2t_1)^2 is this like your formula?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1so D is the displacement? and (t_2  t_1) is the time it takes of the pot to fall past the window

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1how much displacement is is this example?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1so we have ( v_i = v_y0 ) D = v_i t + 1/2 g t^2 lets solve this equation for v_i, the velocity of the pot plant when it was falling past the top the the window and Then, calculate with D = 1.90 m t = 0.420 s g = 9.80 m/s^2

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1what do you get when you rearrange the equation ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that we only need?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1now we have the initial velocity , we still need to work out the height to the window sill

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1Do you have formulas you can just use, or is the derivation helpful?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm.. idk which formula to use lol

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1we need to find the distance to the windowsill from the lower window, we have the velocities

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1do you have a set of 5 equations of projectile motion?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1or i suppose we can say the the pot started on the sill at rest, and was falling at 2.4658 m/s, at the top on the next window down how long was it falling ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we dont learn projectile from now so i really dont know
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