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anonymous
 one year ago
What is the standard form of the equation of a circle with its center at (2, 3) and passing through the point (2, 0)?
anonymous
 one year ago
What is the standard form of the equation of a circle with its center at (2, 3) and passing through the point (2, 0)?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Standard form equation for a circle with center (h,k) and radius r is: (x−h)2+(y−k)2=r2 So you have the center, now you just need the radius. Well, given the center and a point on the circle, the radius is just the distance between those 2 points. so use the distance formula to find the distance between those 2 points, which is your r: d=(x1−x2)2+(y1−y2)2−−−−−−−−−−−−−−−−−−√ Then plug your center point coordinates, and your r, back into the circle equation that I gave you above.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(xh)^2 + (yk)^2= r^2. d = sqrt [(x1x2)^2 + (y1y2)^2]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0SRry forgot to mention square properly
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