anonymous
  • anonymous
HELP PLEASE HELP MEEEEEEEEEEEEEEEE MEDALS+FAN!!!!!!!!!!!!!!!!!!!!!!! Solve using the guess-and-test strategy. The math club has 57 members who are in sixth or seventh grades. There are twice as many sixth graders as seventh graders. How many sixth graders are in the club? A. 38 B. 37 C. 19 D. 18
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
38
jjwalton04
  • jjwalton04
its a because 38/2=19 and 19+38 is 57
jjwalton04
  • jjwalton04
BEWM

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anonymous
  • anonymous
i believe b
anonymous
  • anonymous
ya b
jjwalton04
  • jjwalton04
explain then runninthruthe6
anonymous
  • anonymous
oh nvm
anonymous
  • anonymous
thank u I wish I could all u guys a medal
jjwalton04
  • jjwalton04
well we can give each other medals
anonymous
  • anonymous
2y +y = 57 Then solve for y: 3y = 57 y = 19 But remember "y" is the number of 7th graders. So now that we know what "y" is, we can plug that value into the original equation and solve for x (the # of 6th graders). x + 19 = 57 x = 38
anonymous
  • anonymous
X=2y

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