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- anonymous

HELP PLEASE HELP MEEEEEEEEEEEEEEEE MEDALS+FAN!!!!!!!!!!!!!!!!!!!!!!! Solve using the guess-and-test strategy.
The math club has 57 members who are in sixth or seventh grades. There are twice as many sixth graders as seventh graders.
How many sixth graders are in the club?
A.
38
B.
37
C.
19
D.
18

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- anonymous

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- anonymous

38

- jjwalton04

its a because 38/2=19 and 19+38 is 57

- jjwalton04

BEWM

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- anonymous

i believe b

- anonymous

ya b

- jjwalton04

explain then runninthruthe6

- anonymous

oh nvm

- anonymous

thank u I wish I could all u guys a medal

- jjwalton04

well we can give each other medals

- anonymous

2y +y = 57
Then solve for y:
3y = 57
y = 19
But remember "y" is the number of 7th graders. So now that we know what "y" is, we can plug that value into the original equation and solve for x (the # of 6th graders).
x + 19 = 57
x = 38

- anonymous

X=2y

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