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anonymous

  • one year ago

HELP PLEASE HELP MEEEEEEEEEEEEEEEE MEDALS+FAN!!!!!!!!!!!!!!!!!!!!!!! Solve using the guess-and-test strategy. The math club has 57 members who are in sixth or seventh grades. There are twice as many sixth graders as seventh graders. How many sixth graders are in the club? A. 38 B. 37 C. 19 D. 18

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  1. anonymous
    • one year ago
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    38

  2. jjwalton04
    • one year ago
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    its a because 38/2=19 and 19+38 is 57

  3. jjwalton04
    • one year ago
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    BEWM

  4. anonymous
    • one year ago
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    i believe b

  5. anonymous
    • one year ago
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    ya b

  6. jjwalton04
    • one year ago
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    explain then runninthruthe6

  7. anonymous
    • one year ago
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    oh nvm

  8. anonymous
    • one year ago
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    thank u I wish I could all u guys a medal

  9. jjwalton04
    • one year ago
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    well we can give each other medals

  10. anonymous
    • one year ago
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    2y +y = 57 Then solve for y: 3y = 57 y = 19 But remember "y" is the number of 7th graders. So now that we know what "y" is, we can plug that value into the original equation and solve for x (the # of 6th graders). x + 19 = 57 x = 38

  11. anonymous
    • one year ago
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    X=2y

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