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iwanttogotostanford
 one year ago
Using the completingthesquare method, rewrite f(x) = x^2 − 8x + 3 in vertex form.
iwanttogotostanford
 one year ago
Using the completingthesquare method, rewrite f(x) = x^2 − 8x + 3 in vertex form.

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iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0@urbanmorgans @jjwalton04 @Rishi_K

iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0WOULD IT BE: f(x) = (x − 4)2 + 3??

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.0do they have the same product?

iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0these are my choices: f(x) = (x − 8)2 f(x) = (x − 4)2 − 13 f(x) = (x − 4)2 + 3 f(x) = (x − 4)2 + 16

iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0yes they do @jjwalton04

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x23456y−9−12−13−12−9

iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0so, would it be C???

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.0is that the only one with the same product?

iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0not sure...

iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0is this answer right> Which of the following values "completes the square," or creates a perfect square trinomial, for x2 − 12x + ___? –6 12 36 –36 i think it is C

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1\[\large (x4)^2 + 3 = x^2  8x + 16 + 3 = x^2  8x + 19\] Doesn't look the same to me \[\large x^2  8x + 3\] Complete the square...subtract 3 from both sides of the equation \[\large x^2  8x = 3\] Take half the coefficient of the 'x'...and square it...add that to both sides \[\large x^2  8x + 16 = 3 + 16\] Rewrite as sum of squares \[\large (x4)^2 = 13\] Finally subtract 13 from both sides to get vertex form \[\large (x4)^2  13\]

iwanttogotostanford
 one year ago
Best ResponseYou've already chosen the best response.0@johnweldon1993 ok, thank you !!!! i would've gotten that wrong then...

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.0i think the answer for your second question is 36 though

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.0@johnweldon1993 am i right?
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