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anonymous
 one year ago
Where does the graph of y = sin x from x = 0 to x = 2π start?
anonymous
 one year ago
Where does the graph of y = sin x from x = 0 to x = 2π start?

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butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2A simple way to approach this question is to simply plug in "x = 0" into "y = sin x" so work out what y = sin 0 equals to and this will tell you where the graph begins :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer is at its maximum?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2hmm.. what do you mean?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2Do you know what your standard y = sinx graph looks like? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure what that is I just got into trig today

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2hmm.. okay. Well here's what your standard y = sinx graph will look like : http://www.wolframalpha.com/input/?i=y+%3D+sinx+ And here's what your y= sinx graph will look like from x = 0 to x = 2pi http://www.wolframalpha.com/input/?i=y+%3D+sinx+from+x+%3D+0+to+x+%3D+2pi

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2Since they've told us the boundaries (so the start and end of your graph) are x = 0 and x = 2pi. I guess you could say that the graph starts at (0,0) right? Since x = 0, and if we sub that into our equation : y = sinx... we get: y = sin 0 = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you for the help much appreciated!

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2You're welcome ^_^!
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