Where does the graph of y = sin x from x = 0 to x = 2π start?
Stacey Warren - Expert brainly.com
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A simple way to approach this question is to simply plug in "x = 0" into "y = sin x"
so work out what y = sin 0 equals to and this will tell you where the graph begins :)
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Do you know what your standard y = sinx graph looks like? :)
im not sure what that is I just got into trig today
Well here's what your standard y = sinx graph will look like :
And here's what your y= sinx graph will look like from x = 0 to x = 2pi
Since they've told us the boundaries (so the start and end of your graph) are x = 0 and x = 2pi.
I guess you could say that the graph starts at (0,0) right?
Since x = 0, and if we sub that into our equation : y = sinx... we get:
y = sin 0 = 0