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anonymous

  • one year ago

SIMPLIFY (8x+7x)(4x^3-5x^2-6x+1)

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  1. anonymous
    • one year ago
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    I got this!

  2. anonymous
    • one year ago
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    okay

  3. anonymous
    • one year ago
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    I got this lol

  4. anonymous
    • one year ago
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    Bro....I got this!

  5. anonymous
    • one year ago
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    9x(4x^3-5x^2)+1.....I believe this is it. Let me check again.

  6. anonymous
    • one year ago
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    I think i got it

  7. anonymous
    • one year ago
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    @BlooooooBlahBLIIIIK what did you get?

  8. anonymous
    • one year ago
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    my brain?

  9. anonymous
    • one year ago
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    The answer silly! :P

  10. anonymous
    • one year ago
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    wait 9x(4x^3-5x^2)+1?

  11. anonymous
    • one year ago
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    hold on

  12. anonymous
    • one year ago
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    That's what I got...you can't combined anymore like terms.

  13. anonymous
    • one year ago
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    @coffee789 What did you come up with?

  14. anonymous
    • one year ago
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    Yeah

  15. Nnesha
    • one year ago
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    9x where is it come from ?

  16. anonymous
    • one year ago
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    60x^4-75x^3-90x^2+15x

  17. anonymous
    • one year ago
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    thas wat i got

  18. Nnesha
    • one year ago
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    @coffee789 are you sure it's (8x+7x) >???

  19. anonymous
    • one year ago
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    @Nnesha thats what im trying to figure out

  20. anonymous
    • one year ago
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    yes im sure

  21. anonymous
    • one year ago
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    8x+7x=15x

  22. Nnesha
    • one year ago
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    alright then first combine like terms 8x+7x= ?

  23. anonymous
    • one year ago
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    yea and you get 15x

  24. anonymous
    • one year ago
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    wouldnt it be 15x(4x3−5x2−6x+1)

  25. anonymous
    • one year ago
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    Then you subtract -6x from 15x

  26. anonymous
    • one year ago
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    That's how you get 9x

  27. Nnesha
    • one year ago
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    |dw:1442333350297:dw| multiply all terms by 15xx

  28. Nnesha
    • one year ago
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    15x***

  29. anonymous
    • one year ago
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    Well i got 15x(4x3−5x2−6x+1) idk

  30. Nnesha
    • one year ago
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    @coffee789 multiply all these terms 4x^3-5x^2 -6x+1 by 15x |dw:1442333445816:dw|

  31. Nnesha
    • one year ago
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    15x times 4x^3 = ??

  32. anonymous
    • one year ago
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    60x4

  33. anonymous
    • one year ago
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    ?

  34. Nnesha
    • one year ago
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    multiply the coefficient and add exponents of variables\[\huge\rm 15x^1 ·4x^3=(15 · 4)x^{1+3}\] when we multiply same variables we should add their exponents x is same as x to the 1 power

  35. Nnesha
    • one year ago
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    plz let him solve it

  36. anonymous
    • one year ago
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    Oh sorry

  37. anonymous
    • one year ago
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    okay so i got 60x^4

  38. anonymous
    • one year ago
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    is that right

  39. anonymous
    • one year ago
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    yes

  40. Nnesha
    • one year ago
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    yeah.... right now multiply 15x by 2nd term |dw:1442333740672:dw|

  41. Nnesha
    • one year ago
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    15x times -5x^2 = ?

  42. anonymous
    • one year ago
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    -75x^3

  43. anonymous
    • one year ago
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    Not negative

  44. anonymous
    • one year ago
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    why not

  45. anonymous
    • one year ago
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    I mean yes Lol

  46. Nnesha
    • one year ago
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    that's right |dw:1442334024818:dw| now multiply 15x by -6x and then by -1

  47. Nnesha
    • one year ago
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    +1**

  48. anonymous
    • one year ago
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    15x +1

  49. Nnesha
    • one year ago
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    well 15x times 1=15x but what about -6x 15x tims -6x=?

  50. anonymous
    • one year ago
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    -90x

  51. anonymous
    • one year ago
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    Correct

  52. anonymous
    • one year ago
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    forgot the 2

  53. anonymous
    • one year ago
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    −90x2

  54. Nnesha
    • one year ago
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    well nope 15x times -6x= ?? remember x is same as x^1 so add their exponents

  55. Nnesha
    • one year ago
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    when we multiply same bases we should add their exponents \[\huge\rm x^1 ·x^1 =x^{1+1}\]

  56. anonymous
    • one year ago
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    oh so it's -90x^2

  57. Nnesha
    • one year ago
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    yes right

  58. Nnesha
    • one year ago
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    that's it done!

  59. anonymous
    • one year ago
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    yayy

  60. anonymous
    • one year ago
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    Yup

  61. Nnesha
    • one year ago
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    Yahoo!! o^_^o

  62. anonymous
    • one year ago
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    thanks for all of your help

  63. Nnesha
    • one year ago
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    yw :=)

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