some.random.cool.kid
  • some.random.cool.kid
New question If anyone has time to spare I have a few questions I need help with
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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some.random.cool.kid
  • some.random.cool.kid
When subtracted, what is the simplified form of (54 − 27i) − (39 + 5i)? Write the answer in standard form, a + bi, where a and b are real numbers.
some.random.cool.kid
  • some.random.cool.kid
I know I have to distribute and also I can do like terms
Nnesha
  • Nnesha
distribute 2nd parentheses by negative one

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some.random.cool.kid
  • some.random.cool.kid
yeah igot tha tpart already im confused as to the rest...
Nnesha
  • Nnesha
alright show ur work
some.random.cool.kid
  • some.random.cool.kid
well this is what I have so far 54 − 27i) − (39 + 5i) 27{-1} - 5{-1} thats the part I was stuck on and Dont I have to change the sign when canceling or something like that?
some.random.cool.kid
  • some.random.cool.kid
then 54 minus the 39 and now im stuck.
some.random.cool.kid
  • some.random.cool.kid
I bleive its 15 addition to something
Nnesha
  • Nnesha
well you didn't distribute the 2nd parentheses
Nnesha
  • Nnesha
why is it 27{-1} = ?
some.random.cool.kid
  • some.random.cool.kid
sq to power of 2?
some.random.cool.kid
  • some.random.cool.kid
-1 x -1 imaginary number
Nnesha
  • Nnesha
oh well no i = sqrt{-1} i^2 = -1 but there isn't any i^2
some.random.cool.kid
  • some.random.cool.kid
so its not power of two?
Nnesha
  • Nnesha
|dw:1442334862171:dw| well we don't have to apply the foil method distribute 2nd parenthesizes by -1 and then combine like terms
some.random.cool.kid
  • some.random.cool.kid
uh -5?
some.random.cool.kid
  • some.random.cool.kid
i
some.random.cool.kid
  • some.random.cool.kid
so 27i + -5i?
Nnesha
  • Nnesha
welll leave the first parentheses alone for first step \[\huge\rm -1(39+5i)\] distribute multiply both terms in the parentheses by negative 1
some.random.cool.kid
  • some.random.cool.kid
so -39 + -5i?
Nnesha
  • Nnesha
yes right
some.random.cool.kid
  • some.random.cool.kid
i thought you needed like terms?
Nnesha
  • Nnesha
yes right now we have like terms |dw:1442335143368:dw| combine like terms
some.random.cool.kid
  • some.random.cool.kid
32i btw
Nnesha
  • Nnesha
if we have negative sign outside the parentheses we must hve to distribute first
Nnesha
  • Nnesha
hmm -27i-5i = ?
some.random.cool.kid
  • some.random.cool.kid
i guess so
some.random.cool.kid
  • some.random.cool.kid
but it has minus
Nnesha
  • Nnesha
yes it supposed to be -32 -# -# = -#
some.random.cool.kid
  • some.random.cool.kid
so far i se 15 - 32i? am I steearing in the righ tdirection?
Nnesha
  • Nnesha
yes that's right
some.random.cool.kid
  • some.random.cool.kid
- hashtag lol
some.random.cool.kid
  • some.random.cool.kid
So am I done now ? because I need help with more if you have time to spare explaining a few with me.
Nnesha
  • Nnesha
yes that's itdone!
some.random.cool.kid
  • some.random.cool.kid
would you mind helping me with this one too? The number root of order seven of fifty three cubed can be written as fifty three to the power of start fraction cap a over cap b end fraction end power. What is the value of A?
some.random.cool.kid
  • some.random.cool.kid
ooo that came out messy maybe I can attach a file
some.random.cool.kid
  • some.random.cool.kid
some.random.cool.kid
  • some.random.cool.kid
some.random.cool.kid
  • some.random.cool.kid
ok done. :D
Nnesha
  • Nnesha
ah okay so can convert root to an exponent form exponent rule \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes the denominator of the fraction
some.random.cool.kid
  • some.random.cool.kid
sorry my internet went bye bye lol
some.random.cool.kid
  • some.random.cool.kid
ok so now what?
Nnesha
  • Nnesha
that's it
some.random.cool.kid
  • some.random.cool.kid
im lost?
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha ah okay so can convert root to an exponent form exponent rule \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes the denominator of the fraction \(\color{blue}{\text{End of Quote}}\) read this
some.random.cool.kid
  • some.random.cool.kid
nvm i got it 7/3?
Nnesha
  • Nnesha
no that's not right
some.random.cool.kid
  • some.random.cool.kid
hmm?
Nnesha
  • Nnesha
index would be the `denominator`
some.random.cool.kid
  • some.random.cool.kid
ooohh ohhh sorry
some.random.cool.kid
  • some.random.cool.kid
get it now
Nnesha
  • Nnesha
alright so A would be what ?
some.random.cool.kid
  • some.random.cool.kid
isnt the 3 the den?
Nnesha
  • Nnesha
yes right
some.random.cool.kid
  • some.random.cool.kid
because the numer became the power
some.random.cool.kid
  • some.random.cool.kid
alright thanks
Nnesha
  • Nnesha
excellent! yw good work!

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