New question If anyone has time to spare I have a few questions I need help with

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New question If anyone has time to spare I have a few questions I need help with

Mathematics
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When subtracted, what is the simplified form of (54 − 27i) − (39 + 5i)? Write the answer in standard form, a + bi, where a and b are real numbers.
I know I have to distribute and also I can do like terms
distribute 2nd parentheses by negative one

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yeah igot tha tpart already im confused as to the rest...
alright show ur work
well this is what I have so far 54 − 27i) − (39 + 5i) 27{-1} - 5{-1} thats the part I was stuck on and Dont I have to change the sign when canceling or something like that?
then 54 minus the 39 and now im stuck.
I bleive its 15 addition to something
well you didn't distribute the 2nd parentheses
why is it 27{-1} = ?
sq to power of 2?
-1 x -1 imaginary number
oh well no i = sqrt{-1} i^2 = -1 but there isn't any i^2
so its not power of two?
|dw:1442334862171:dw| well we don't have to apply the foil method distribute 2nd parenthesizes by -1 and then combine like terms
uh -5?
i
so 27i + -5i?
welll leave the first parentheses alone for first step \[\huge\rm -1(39+5i)\] distribute multiply both terms in the parentheses by negative 1
so -39 + -5i?
yes right
i thought you needed like terms?
yes right now we have like terms |dw:1442335143368:dw| combine like terms
32i btw
if we have negative sign outside the parentheses we must hve to distribute first
hmm -27i-5i = ?
i guess so
but it has minus
yes it supposed to be -32 -# -# = -#
so far i se 15 - 32i? am I steearing in the righ tdirection?
yes that's right
- hashtag lol
So am I done now ? because I need help with more if you have time to spare explaining a few with me.
yes that's itdone!
would you mind helping me with this one too? The number root of order seven of fifty three cubed can be written as fifty three to the power of start fraction cap a over cap b end fraction end power. What is the value of A?
ooo that came out messy maybe I can attach a file
ok done. :D
ah okay so can convert root to an exponent form exponent rule \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes the denominator of the fraction
sorry my internet went bye bye lol
ok so now what?
that's it
im lost?
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha ah okay so can convert root to an exponent form exponent rule \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes the denominator of the fraction \(\color{blue}{\text{End of Quote}}\) read this
nvm i got it 7/3?
no that's not right
hmm?
index would be the `denominator`
ooohh ohhh sorry
get it now
alright so A would be what ?
isnt the 3 the den?
yes right
because the numer became the power
alright thanks
excellent! yw good work!

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