New question If anyone has time to spare I have a few questions I need help with

- some.random.cool.kid

New question If anyone has time to spare I have a few questions I need help with

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- some.random.cool.kid

When subtracted, what is the simplified form of (54 − 27i) − (39 + 5i)? Write the answer in standard form, a + bi, where a and b are real numbers.

- some.random.cool.kid

I know I have to distribute and also I can do like terms

- Nnesha

distribute 2nd parentheses by negative one

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## More answers

- some.random.cool.kid

yeah igot tha tpart already im confused as to the rest...

- Nnesha

alright show ur work

- some.random.cool.kid

well this is what I have so far
54 − 27i) − (39 + 5i)
27{-1} - 5{-1} thats the part I was stuck on and Dont I have to change the sign when canceling or something like that?

- some.random.cool.kid

then 54 minus the 39 and now im stuck.

- some.random.cool.kid

I bleive its 15 addition to something

- Nnesha

well you didn't distribute the 2nd parentheses

- Nnesha

why is it 27{-1} = ?

- some.random.cool.kid

sq to power of 2?

- some.random.cool.kid

-1 x -1 imaginary number

- Nnesha

oh well no i = sqrt{-1}
i^2 = -1
but there isn't any i^2

- some.random.cool.kid

so its not power of two?

- Nnesha

|dw:1442334862171:dw|
well we don't have to apply the foil method
distribute 2nd parenthesizes by -1
and then combine like terms

- some.random.cool.kid

uh -5?

- some.random.cool.kid

i

- some.random.cool.kid

so 27i + -5i?

- Nnesha

welll leave the first parentheses alone for first step \[\huge\rm -1(39+5i)\] distribute
multiply both terms in the parentheses by negative 1

- some.random.cool.kid

so -39 + -5i?

- Nnesha

yes right

- some.random.cool.kid

i thought you needed like terms?

- Nnesha

yes right now we have like terms |dw:1442335143368:dw|
combine like terms

- some.random.cool.kid

32i btw

- Nnesha

if we have negative sign outside the parentheses we must hve to distribute first

- Nnesha

hmm -27i-5i = ?

- some.random.cool.kid

i guess so

- some.random.cool.kid

but it has minus

- Nnesha

yes it supposed to be -32
-# -# = -#

- some.random.cool.kid

so far i se 15 - 32i? am I steearing in the righ tdirection?

- Nnesha

yes that's right

- some.random.cool.kid

- hashtag lol

- some.random.cool.kid

So am I done now ? because I need help with more if you have time to spare explaining a few with me.

- Nnesha

yes that's itdone!

- some.random.cool.kid

would you mind helping me with this one too?
The number root of order seven of fifty three cubed can be written as fifty three to the power of start fraction cap a over cap b end fraction end power. What is the value of A?

- some.random.cool.kid

ooo that came out messy maybe I can attach a file

- some.random.cool.kid

##### 1 Attachment

- some.random.cool.kid

##### 1 Attachment

- some.random.cool.kid

ok done. :D

- Nnesha

ah okay so can convert root to an exponent form
exponent rule \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes the denominator of the fraction

- some.random.cool.kid

sorry my internet went bye bye lol

- some.random.cool.kid

ok so now what?

- Nnesha

that's it

- some.random.cool.kid

im lost?

- Nnesha

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
ah okay so can convert root to an exponent form
exponent rule \[\huge\rm \sqrt[n]{x^m}=x^\frac{ m }{ n }\] index becomes the denominator of the fraction
\(\color{blue}{\text{End of Quote}}\)
read this

- some.random.cool.kid

nvm i got it 7/3?

- Nnesha

no that's not right

- some.random.cool.kid

hmm?

- Nnesha

index would be the `denominator`

- some.random.cool.kid

ooohh ohhh sorry

- some.random.cool.kid

get it now

- Nnesha

alright so A would be what ?

- some.random.cool.kid

isnt the 3 the den?

- Nnesha

yes right

- some.random.cool.kid

because the numer became the power

- some.random.cool.kid

alright thanks

- Nnesha

excellent!
yw good work!

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