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anonymous
 one year ago
Calculate the average rate of change for the given graph from x = –2 to x = 0 and select the correct answer below.
anonymous
 one year ago
Calculate the average rate of change for the given graph from x = –2 to x = 0 and select the correct answer below.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Courtesy of Texas Instruments 0 1 –1 –2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha @nincompoop @ganeshie8

Baby_Bear69
 one year ago
Best ResponseYou've already chosen the best response.0idk , i'd be guessing C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0C is always my first guess

Baby_Bear69
 one year ago
Best ResponseYou've already chosen the best response.0Haha we tagged him at the same time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know the formula for the average rate of change?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[M = \frac{ {y2}y1 }{ x2x1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So they're asking for the average rate of change from x = 2 to x = 0. So we have two ordered pairs. (2, y1) and (0, y2). On the graph it shows that the y's are both 1. So yes you plug in the ordered pairs into the formula. \[M = \frac{ 1  (1) }{ 0  (2) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What part are you confused on? I'll try to clear it up. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0when i solved the formula i got 2 and that isent one of the answer choices

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You shouldn't get an ordered pair when you solve it. Also, when you put 1  (1) 02. You forgot that the 2 is also negative so it'd actually be 0  (2). The subtraction signs become addition/positive of course. So your equation becomes \[M = \frac{ 1+1 }{ 0 + 2 }\]
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