pinklion23
  • pinklion23
32-6x+7x=(-15)+28 solve for x X=
Mathematics
katieb
  • katieb
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jagr2713
  • jagr2713
Hey what do you think we do first?
pinklion23
  • pinklion23
subtract 32 from both sides
jagr2713
  • jagr2713
Yes you can but don't you want to add like terms first?

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pinklion23
  • pinklion23
oh yeah i forget so 13x
jagr2713
  • jagr2713
you forgot the negative sign.
pinklion23
  • pinklion23
oh ok so 32-(-13x)= (-15)+28?
jagr2713
  • jagr2713
nope -6+7x= 1
pinklion23
  • pinklion23
so then x=1
jagr2713
  • jagr2713
Yes so we have 32+x=(-15)+28 left right? so what next
pinklion23
  • pinklion23
then we do32- 28 so then it would be 4+x=(-15)
jagr2713
  • jagr2713
good what next?
pinklion23
  • pinklion23
the x=-19?
jagr2713
  • jagr2713
Correct :D
pinklion23
  • pinklion23
wow thx so much can you help me with some more?
jagr2713
  • jagr2713
Of course :D
pinklion23
  • pinklion23
-4X+5(X-2)=-16+10
jagr2713
  • jagr2713
what do we do first?
pinklion23
  • pinklion23
-16+10?
jagr2713
  • jagr2713
yea you can so we get -6
jagr2713
  • jagr2713
-4x+5(x-2)=-6 whats next?
pinklion23
  • pinklion23
yeah
pinklion23
  • pinklion23
um then we do -6-2?
jagr2713
  • jagr2713
Nope when we have a number like 5(x-2) we distribute. Do you how to distribute ?
pinklion23
  • pinklion23
so then we do (x*5)-(2*5)
jagr2713
  • jagr2713
Yes like this|dw:1442341177921:dw|
jagr2713
  • jagr2713
So we just multiply everything inside that parenthesis
pinklion23
  • pinklion23
yeah
jagr2713
  • jagr2713
so now we got -4x+5x-10=-6 whats next
pinklion23
  • pinklion23
then we have 1x-10=-6
jagr2713
  • jagr2713
It's not 1x x=1 so u don't need to put the 1
pinklion23
  • pinklion23
the we add -10 to -6
pinklion23
  • pinklion23
?
pinklion23
  • pinklion23
so X=1
jagr2713
  • jagr2713
you got that? x=1 you out 1x-10=-6 but x already is 1 so u don't need to put the 1x just x-10=-6
pinklion23
  • pinklion23
ok so X = -16
pinklion23
  • pinklion23
or -4
jagr2713
  • jagr2713
nope -6+10?
jagr2713
  • jagr2713
positive 4 :D
pinklion23
  • pinklion23
oh ok thx
jagr2713
  • jagr2713
Yep Anytime :D
pinklion23
  • pinklion23
i have two more can you help me with them
jagr2713
  • jagr2713
ummm ill see what i can do :D

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