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OregonDuck

  • one year ago

help with Pythagoras' Theorem

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  1. OregonDuck
    • one year ago
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    the hypotenuse of the right triangle is 13 and the base is 5 what is the height show your work

  2. Nnesha
    • one year ago
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    \[\huge \rm a^2+b^2=c^2\] Pythagorean theorem c is the longest side( hypotenuse ) so plugin c and b value solve for a

  3. OregonDuck
    • one year ago
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    \[5^{2}+b ^{2}=13^{2}\]

  4. Nnesha
    • one year ago
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    looks good solve for b

  5. OregonDuck
    • one year ago
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    how?

  6. Nnesha
    • one year ago
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    btw base is b but that's not gonna change the answer

  7. Nnesha
    • one year ago
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    how would you cancel out 5^2 from left side ? would you add,subtract,multiply or divide by 5^2?

  8. OregonDuck
    • one year ago
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    mulitiply so...\[25+b ^{2}=169\]

  9. Nnesha
    • one year ago
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    that's right 25+b^2=169 now move 25 to the right side so how would you cancel out 25 from left side ?

  10. OregonDuck
    • one year ago
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    idk actullay

  11. Nnesha
    • one year ago
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    it's 25 `+`b^2 25 is positive at left side to cancel it out so should subtract 25 both sides

  12. OregonDuck
    • one year ago
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    i am confused

  13. Nnesha
    • one year ago
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    \[\huge\rm 25 +b^2=169\] we have to solve for b so subtract 25 both sides

  14. OregonDuck
    • one year ago
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    25=144

  15. Nnesha
    • one year ago
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    |dw:1442344735597:dw| both sides what would you get when you subtract 25 at left side ?

  16. OregonDuck
    • one year ago
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    0 and on the right 144

  17. Nnesha
    • one year ago
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    yes right |dw:1442344859009:dw| to cancel out the `square` you should take `square root both sides`

  18. OregonDuck
    • one year ago
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    ok so it is 12? right the answer for the hieght

  19. Nnesha
    • one year ago
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    yes right

  20. OregonDuck
    • one year ago
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    ok sweet thxs so much

  21. Nnesha
    • one year ago
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    yw :=)

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