## BloomLocke367 one year ago Is it possible to have a piecewise function with only part of a circle?.. I know the equation isn't a function so I'm not sure if it's an actual thing...

1. anonymous

I believe it's possible if you specify the domain.

2. anonymous

The only issue is the co-variant nature of that circle.

3. BloomLocke367

I tried and it didn't do it :O that's why I was wondering.. I have a project where I have to make a picture using piecewise functions and I only need part of a circle but I can't figure out how to do it.

4. BloomLocke367

@Nnesha

5. BloomLocke367

@Shalante

6. anonymous

I am too trying to figure out how piecewise function works for my brother

7. anonymous

It appears pretty intuitive until you figure out each specified domain must also account for different equations.

8. BloomLocke367

okay.. hmm

9. BloomLocke367

@King.Void.

10. King.Void.

Not good at math

11. BloomLocke367

dang ok

12. beginnersmind

Think about the function $f(x)= \sqrt{1-x^2}$ compare it with the equation of a circle of radius 1 centered on the origin: $x^2+y^2 = 1$

13. BloomLocke367

@Shalante

14. anonymous

you can have a function alone, and be only a semi-circle a circle is compounded of two semicircles really each semi-circle occurs when you use the square root the square root has a + and a - part, thus $$\large \pm \sqrt{\quad}$$

15. BloomLocke367

that only shows half of the circle..

16. BloomLocke367

yea okay XD I was about to say..

17. BloomLocke367

but I'm working on a piecewise project and I have to create a picture on a graph using piecewise functions and that's why I was wondering XD