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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}(g(f(x))) = g'(f(x)) \cdot f'(x)\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2and hi @Jhannybean !!

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Hi everyone xD Thanks for helping me!!

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2you have all the numbers you need to plug in to what @Jhannybean wrote above plug them in, see what you get

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Wait so I understand how to plug in the f(x) and f'(x) but how do I do the g(x) and g'(x)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2let me just add one little bit \[\frac{d}{dx}(g(f(3x))) = g'(f(3x)) \cdot f'(3x)\cdot 3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now we have \(g'(f(x)) \cdot f'(x)\) take it one step at a time. \[g'(f(1)) \cdot f'(1)=~?\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2careful a little it is \(f(3x)\) so at \(x=1\) it is \(f(3)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oooo stupid me. I misread a portion of the problem.

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0So if x=1 at f(3x) = f(3) what am i supposed to use to plug in.. im actually really confused

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2now got to read them off of the table at \(x=1\) it is \[g'(f(3)) \cdot f'(3)\cdot 3\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2what is \(f'(3)\) from the table?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and what is \(f(3)\) from the table?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2and finally, what is \(g'(2)\)?

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0So would it be 5(10)(3)=150?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2number therapy for learning the chain rule

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Haha thank you so much! Okay so would that be how you do it at x=1 or is that just an example from the chart?

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay i understand so we just broke it up into components

tmagloire1
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much both of you for your help!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[g'(f(1))\cdot f'(1) = \\ g'(f(3(1))) \cdot f'(3(1)) \cdot 3 = \\ g'(f(3)) \cdot f'(3) \cdot 3 = \\ g'(2) \cdot 10\cdot 3 = \\ 5 \cdot 10\cdot 3 = 150\]
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