anonymous
  • anonymous
Little confused on this? Just working on parametric equations, I have x= sin theta/2 & y = cos theta/2... and I have to create a plot table between -pie and pie. I don't know if Im supposed to use the radians as the parameter for the plot table or just degrees? i'm confused...
Mathematics
chestercat
  • chestercat
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misty1212
  • misty1212
HI!!
misty1212
  • misty1212
always use radians, they are numbers
misty1212
  • misty1212
if it is \[x=\sin(\frac{\theta}{2}), y=\cos(\frac{\theta}{2})\] you should get a circle

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misty1212
  • misty1212
actually because of the \(\frac{\theta}{2}\) you get the upper half of a circle
anonymous
  • anonymous
right, I see how it's a circle, i'm just a little confused on the radians, because I'm not understanding what values are supposed to correspond on the table?... I'm sorry if this is confusing, because I'm barely refreshing my trig values and stuff, and I'm not understanding just what values do I use as the parameter...
anonymous
  • anonymous
so would my value -pie correspond to -1? say for like the first value on my table?... if I was just plugging in the value for sin 0/2?
zepdrix
  • zepdrix
I guess the start of your interval, \(\rm \theta=-\pi\) would correspond to \(\rm (x,y)=(-1,0)\) yes?
misty1212
  • misty1212
here is a nice picture this is what you should get http://www.wolframalpha.com/input/?i=x%3Dsin%28t%2F2%29%2Cy%3Dcos%28t%2F2%29%2C+t+from+-pi+to+pi
anonymous
  • anonymous
ok. great. So If i was plotting the points for the table and I started at -pi, and then -3pi/2, -pi/2, etc. up to pi. Would I just plug in the corresponding degree into the function to be able to graph it by hand.. for example, x= sin theta/2 I would plug in for first value sin 1/2 to get my x coordinate?
misty1212
  • misty1212
at \(-\pi\) you get \[(\sin(-\frac{\pi}{2}),\cos(-\frac{\pi}{2}))=(0,-1)\]
zepdrix
  • zepdrix
Ahh woops :) I just assumed sine went with the y coordinate haha
misty1212
  • misty1212
yeah it usually does, doesn't it?
zepdrix
  • zepdrix
Oh maybe I didn't... sin(-pi/2) = -1
zepdrix
  • zepdrix
Ya I think misty has those backwards :d
anonymous
  • anonymous
ok. great. I see what your saying, so If I was to plug in the value for -3pi/2 do I just convert that into degrees and make it sin -3pi/2 /2 ?
misty1212
  • misty1212
lol totally backwards
misty1212
  • misty1212
i did the cosine first and the sine second, same mistake doe!
zepdrix
  • zepdrix
degrees? ew ew ew :( \[\large\rm \frac{3\pi/2}{2}=\frac{3\pi}{4}\]
anonymous
  • anonymous
oh. ok. I understand now. great. thank you, Yes I was not understanding the x y points. thank you

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