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anonymous
 one year ago
Little confused on this? Just working on parametric equations, I have x= sin theta/2 & y = cos theta/2... and I have to create a plot table between pie and pie. I don't know if Im supposed to use the radians as the parameter for the plot table or just degrees? i'm confused...
anonymous
 one year ago
Little confused on this? Just working on parametric equations, I have x= sin theta/2 & y = cos theta/2... and I have to create a plot table between pie and pie. I don't know if Im supposed to use the radians as the parameter for the plot table or just degrees? i'm confused...

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.2always use radians, they are numbers

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2if it is \[x=\sin(\frac{\theta}{2}), y=\cos(\frac{\theta}{2})\] you should get a circle

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2actually because of the \(\frac{\theta}{2}\) you get the upper half of a circle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right, I see how it's a circle, i'm just a little confused on the radians, because I'm not understanding what values are supposed to correspond on the table?... I'm sorry if this is confusing, because I'm barely refreshing my trig values and stuff, and I'm not understanding just what values do I use as the parameter...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would my value pie correspond to 1? say for like the first value on my table?... if I was just plugging in the value for sin 0/2?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0I guess the start of your interval, \(\rm \theta=\pi\) would correspond to \(\rm (x,y)=(1,0)\) yes?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2here is a nice picture this is what you should get http://www.wolframalpha.com/input/?i=x%3Dsin%28t%2F2%29%2Cy%3Dcos%28t%2F2%29%2C+t+from+pi+to+pi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. great. So If i was plotting the points for the table and I started at pi, and then 3pi/2, pi/2, etc. up to pi. Would I just plug in the corresponding degree into the function to be able to graph it by hand.. for example, x= sin theta/2 I would plug in for first value sin 1/2 to get my x coordinate?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2at \(\pi\) you get \[(\sin(\frac{\pi}{2}),\cos(\frac{\pi}{2}))=(0,1)\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Ahh woops :) I just assumed sine went with the y coordinate haha

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2yeah it usually does, doesn't it?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Oh maybe I didn't... sin(pi/2) = 1

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Ya I think misty has those backwards :d

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. great. I see what your saying, so If I was to plug in the value for 3pi/2 do I just convert that into degrees and make it sin 3pi/2 /2 ?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2lol totally backwards

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2i did the cosine first and the sine second, same mistake doe!

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0degrees? ew ew ew :( \[\large\rm \frac{3\pi/2}{2}=\frac{3\pi}{4}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh. ok. I understand now. great. thank you, Yes I was not understanding the x y points. thank you
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