anonymous
  • anonymous
Fan and medal HELP PLEASE !! When a ball is thrown, the path it travels is a parabola. Suppose a baseball is thrown from ground level, reaches a maximum height of 50 feet, and hits the ground 200 feet from where it was thrown. Assuming this situation could be modeled on a coordinate plane with the focus of the parabola at the origin, find the equation of the parabolic path of the ball. Assume the focus is on ground level. ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Jhannybean
  • Jhannybean
|dw:1442354060646:dw|
anonymous
  • anonymous
can you explain how I can find the equation, this confused me a lot :(
Jhannybean
  • Jhannybean
Hmm... let's try drawing it on a coordinate plane. |dw:1442354849953:dw|

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Jhannybean
  • Jhannybean
So you're given: \[\sf \text{focus}~=~(0,0) \\ \text{vertex}~=~ (0,50) = (h,k) \\ p = 50 : (\text{distance between the vertex and the focus, or focus and directrix}) \]\[4p(y-k)=(x-h)^2\]
Jhannybean
  • Jhannybean
Are you able to solve this now?
Jhannybean
  • Jhannybean
Oh, sorry, meant to say that: p is the distance from focus to vertex, or VERTEX to directrix. These two relations make the directrix equidistant from the vertex, and the vertex equidistant from the focus.
anonymous
  • anonymous
okay thank you I understand now :)
Jhannybean
  • Jhannybean
Wonderful!

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