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anonymous

  • one year ago

Fan and medal HELP PLEASE !! When a ball is thrown, the path it travels is a parabola. Suppose a baseball is thrown from ground level, reaches a maximum height of 50 feet, and hits the ground 200 feet from where it was thrown. Assuming this situation could be modeled on a coordinate plane with the focus of the parabola at the origin, find the equation of the parabolic path of the ball. Assume the focus is on ground level. ?

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  1. Jhannybean
    • one year ago
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    |dw:1442354060646:dw|

  2. anonymous
    • one year ago
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    can you explain how I can find the equation, this confused me a lot :(

  3. Jhannybean
    • one year ago
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    Hmm... let's try drawing it on a coordinate plane. |dw:1442354849953:dw|

  4. Jhannybean
    • one year ago
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    So you're given: \[\sf \text{focus}~=~(0,0) \\ \text{vertex}~=~ (0,50) = (h,k) \\ p = 50 : (\text{distance between the vertex and the focus, or focus and directrix}) \]\[4p(y-k)=(x-h)^2\]

  5. Jhannybean
    • one year ago
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    Are you able to solve this now?

  6. Jhannybean
    • one year ago
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    Oh, sorry, meant to say that: p is the distance from focus to vertex, or VERTEX to directrix. These two relations make the directrix equidistant from the vertex, and the vertex equidistant from the focus.

  7. anonymous
    • one year ago
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    okay thank you I understand now :)

  8. Jhannybean
    • one year ago
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    Wonderful!

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