## anonymous one year ago Horizontal translation of a quartic function by 30 y=-x^3+138x

1. anonymous

I need to figure how how I can translate this equation to the right by 30

2. anonymous

I know this looks pretty rudimentary but trust me I don't know how

3. zepdrix

Hey Robert :) In general, to make an horizontal adjustment, we would compensate by doing the opposite to our x. So here is an example with a simple quadratic.$\large\rm f(x)=(x)^2$To shift it 30 to the right (positive), ill replace x with x-30,$\large\rm g(x)=(x-30)^2$This new function g(x) is the same shape as f(x) but the whole thing has been shifted to the right 30 units.

4. zepdrix

So we have a cubic function and we want to apply the same idea, (not a quartic silly :3 ) $\large\rm y_1=-\color{orangered}{x}^3+138\color{orangered}{x}$$\large\rm y_2=-\color{orangered}{(x-30)}^3+138\color{orangered}{(x-30)}$And then maybe you'll have to expand some brackets out if you want to get it into standard form.

5. anonymous

Oh I see it now. I have to apply the same shift to all the variables.

6. anonymous

Thanks so much @zepdrix Are you taking university math?

7. zepdrix

Yesss :) Learning lots of fun stuff!!

Find more explanations on OpenStudy