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anonymous

  • one year ago

the midpoints of UV are (5,-11). The coordinates of one endpoint are U(3,5). find the coordinates of endpoint V. I don't understand this at all :?

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  1. jdoe0001
    • one year ago
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    have you covered the midpoint formula yet?

  2. anonymous
    • one year ago
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    yes, |dw:1442358085631:dw|

  3. anonymous
    • one year ago
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    (5, -11)

  4. jdoe0001
    • one year ago
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    right so... we know the MidPoint is (5,-11) the whole segment is UV we know what U is, is (3,5) we dunno what V is so one sec

  5. anonymous
    • one year ago
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    |dw:1442358296247:dw|

  6. anonymous
    • one year ago
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    |dw:1442358320009:dw|

  7. anonymous
    • one year ago
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    |dw:1442358350329:dw|

  8. anonymous
    • one year ago
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    |dw:1442358362868:dw|

  9. anonymous
    • one year ago
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    |dw:1442358425571:dw|

  10. anonymous
    • one year ago
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    |dw:1442358469597:dw|

  11. anonymous
    • one year ago
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    |dw:1442358487776:dw|

  12. jdoe0001
    • one year ago
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    \(\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &U({\color{red}{ 3}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) &V({\color{red}{ V_x}}\quad ,&{\color{blue}{ V_y}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right) \\ \quad \\ \left(\cfrac{{\color{red}{ V_x}} + {\color{red}{ 3}}}{2}\quad ,\quad \cfrac{{\color{blue}{ V_y}} + {\color{blue}{ 5}}}{2} \right)=(5,-11)\qquad \textit{that means then} \\ \quad \\ \cfrac{{\color{red}{ V_x}} + {\color{red}{ 3}}}{2}=5\qquad and\qquad \cfrac{{\color{blue}{ V_y}} + {\color{blue}{ 5}}}{2}=-11 \\ \quad \\ solve\ for\ V_x\ and\ V_y\ then\)

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